Equivalence of two sets of data

[vsoler]

My problem is as follows:

I have one set of integers and zeroes in A1:Z1 (26 cells)
Another set of integers and zeroes is in A2:Z2

I want to compare the first "n" numbers in A1:Z1 with the first "n"
numbers in A2:Z2; such "n" number is in A3 and may vary depending of
the scenario.

The first "n" integers in A1:Z1 contain no duplicates and no zeroes;
the first "n" integers in A2:Z2 may or may not have duplicates or
zeroes.

I need a formula that gives me "1" if the first "n" integers in A1:Z1
are exactly the same as the first "n" integers in A2:Z2, although they
may be in a different order; the formula would give zero in any other
case.

Can it be done by using one single formula?

Thank you for your help

 

[mrice]

It could certainly be done with a user defined formula which sorted a
array of values from the two columns and compared as many as the valu
of n

 

[Guest]

In cell A3... =IF(A1=A2,1,0)
--
Hope this Helps!
Camilo

Objective: To help one person each day!

Feedback is greatly appreciated! Please let me know if I've answered your
question or if my post was helpful to you?

 

[vsoler]

I'll give you an example

A B C D
1 2 4 1 5 0...
2 5 1 2 4 0...
3 4

That is, if the 4 non repeated integers appear again in the second row,
then the function should return "1"

A B C D
1 2 4 1 5 0...
2 5 1 2 1 0...
3 4

In this case, the function should return "0" because not all the non
repeated integers appear just once in row #2.

I hope you can help

 

[Morrigan]

Not sure what you want exactly, see attachment. Good luck.


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