Distributed File System: Error creating new root

F

Fao, Sean

I've been trying to configure a new distributed file system root on my
Windows 2003 server and have been unsuccessful. I make it through the
wizard until I click the "Finish" button. At this point, an alert is
displayed that says, "The following error occurred while creating DFS
root on server child.domain.com: The specified path is invalid."

The share that I was trying to use is on a drive that has been mounted
inside of a directory (E.G. C:\Shares\ is actually located on another
physical drive then C:\). I suspected this to be the cause of my
problem so I created a new share for my DFS and used the directory,
C:\temp, which is located on the same physical drive as C:\. My
suspicion was confirmed when I was able to create the DFS with no
problems. Is this a bug with the wizard or is it not possible to create
a DFS on these types of directories?

I appreciate any advice and thank you in advance,
 
J

Jill Zoeller [MSFT]

You are correct that DFS cannot create its link folders on a mounted drive.
It's not so much a bug as a design limitation. Do you need to have this
ability? We are investigating whether we need to change this design.

This lmitation did not exist in Windows 2000.
 
F

Fao, Sean

Jill said:
You are correct that DFS cannot create its link folders on a mounted drive.
It's not so much a bug as a design limitation. Do you need to have this
ability? We are investigating whether we need to change this design.

This lmitation did not exist in Windows 2000.

Well, I don't particularly _require_ this ability; however, I must have
some form of phobia of running out of drive letters because I prefer to
mount devices inside of directories, rather than separating devices by
assigning unique drive letters. Then again, I have quite a number of
years of experience in *nix and was pleasantly surprised when I first
saw the feature added in Windows 2000. Does that answer your question?
No, it's not necessary, but yes, it would be nice :).

Thanks for you reply,

Sean
 

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