Delete columns based on cell value

[Robert H]

Im trying to loop through each cell in the first row of a sheet and if
the cell contains the text "ID" the delete that entire column. the
following code works well except it starts at the 11th column instead
of at the first also the curCell value is blank after a certain number
of cells even tho there is still data in the location it is looking
at.

Sub DeleteIDCol()
'removes the LC_ID and QD_ID columns.
Dim colHead As Range
Dim n As Integer
Dim curCell As Range

Set colHead = Rows(1)
For n = 1 To colHead.Columns.Count
Set curCell = Cells(1 & n)
If InStr(1, curCell, "ID") > 0 Then
curCell.EntireColumn.Delete
End If
Next n
End Sub

 

[Guest]

Try changing: Set curCell = Cells(1 & n)
To: Set curCell = Cells(1, n)

 

[Don Guillett]

First work from the back to the front. Correct for wordwrap

Sub DeleteIDCol_Don()
For i = Cells(1, Columns.Count).End(xlToLeft).Column To 1 Step -1
If InStr(UCase(Cells(1, i)), "ID") > 0 Then Columns(i).Delete
Next
End Sub

 

[Robert H]

thanks J, that fixed my code

 

[Guest]

You should take a good look at Don's suggested code. It does the same thing
that you are doing but is more efficient because it only uses the range where
you have data. Your code will chech all 256 cells of each row for each
iteration.

 

[Tom Ogilvy]

Just to add

If InStr(UCase(Cells(1, i)), "ID") > 0 Then . . .

could be

If InStr(1,Cells(1, i),"ID",vbTextcompare) Then . . .

Easier to use the built in capabilities of Instr. If "ID" is in the string,
the result will be non-zero and thus interpreted as True.

 

[Robert H]

Funny you say that J, that just what I did and for the same
reason . Onece I got my code working with your help I step through
it and realized I was looking at every cell. And tried Dons code