K
kpax
Hi,
While debugging my application when an explicit exception is thrown by me
(or an implicit exception is thrown internally) which is not handled
anywhere in the stack,
the execution breaks as expected but I can not continue.
I try start the execution and go back to running mode, but it always comes
to the same line
where the exception is first thrown.
I read about the exceptions and tried to work with the exceptions dialog,
but no change.
It is really killing me, since when I get the exception I have to stop the
program and start it again.
Does any one have any idea how this can be overcome?
Thanks in advance...
Ipek
While debugging my application when an explicit exception is thrown by me
(or an implicit exception is thrown internally) which is not handled
anywhere in the stack,
the execution breaks as expected but I can not continue.
I try start the execution and go back to running mode, but it always comes
to the same line
where the exception is first thrown.
I read about the exceptions and tried to work with the exceptions dialog,
but no change.
It is really killing me, since when I get the exception I have to stop the
program and start it again.
Does any one have any idea how this can be overcome?
Thanks in advance...
Ipek