G
Guest
All Access users,
Good Day,
I have a problem and looking solution.
DateDiff("d",[ParkingDatetime],[DriveOutDateTime])=day/days
I would like see day only if crossed 23.59 other wise response should be zoo.
Regards,
--
Access Keen User
----------------
This post is a suggestion for Microsoft, and Microsoft responds to the
suggestions with the most votes. To vote for this suggestion, click the "I
Agree" button in the message pane. If you do not see the button, follow this
link to open the suggestion in the Microsoft Web-based Newsreader and then
click "I Agree" in the message pane.
http://www.microsoft.com/office/com...7b03&dg=microsoft.public.access.modulesdaovba
Good Day,
I have a problem and looking solution.
DateDiff("d",[ParkingDatetime],[DriveOutDateTime])=day/days
I would like see day only if crossed 23.59 other wise response should be zoo.
Regards,
--
Access Keen User
----------------
This post is a suggestion for Microsoft, and Microsoft responds to the
suggestions with the most votes. To vote for this suggestion, click the "I
Agree" button in the message pane. If you do not see the button, follow this
link to open the suggestion in the Microsoft Web-based Newsreader and then
click "I Agree" in the message pane.
http://www.microsoft.com/office/com...7b03&dg=microsoft.public.access.modulesdaovba