Creating a MyIsEven function

[Horatio J. Bilge, Jr.]

I have a workbook that uses the ISEVEN function. Since some people who use
the workbook may not have ATP installed, I decided to try writing my own
MyIsEven function. It gives the same result as ISEVEN on all of the test
entries I tried, except for numbers greater than 2,147,483,647.

Function MyIsEven(Num As Long) As Boolean
Select Case Right (Num, 1)
Case 0, 2, 4, 6, 8
MyIsEven = True
Case Else
MyIsEven = False
End Select
End Function

I thought of adding an If statement to deal with the large numbers, but it
didn't make any difference:
If Num > 2147483647 Then
Num = Num - 2147483646
End If

I also thought of using MyIsEven(Num As Double), but that introduces
different errors.

For my workbook, what I have will work fine, but I thought I would try to be
as thorough as possible.

 

[Gary''s Student]

Make the argument a string rather than a number:

Function MyIsEven(r As Range) As Boolean
Dim s As String
s = r.Value
Select Case Right(s, 1)
Case 0, 2, 4, 6, 8
MyIsEven = True
Case Else
MyIsEven = False
End Select
End Function

 

[Mike H]

To emulate the ATP ISEVEN then the value needs to be truncated

s = Int(r.Value)

Mike

 

[Horatio J. Bilge, Jr.]

That solves the problem of the big numbers, but it introduces other errors.
Here are some samples:

Value MyIsEven ISEVEN
1.2 TRUE FALSE
abc2 TRUE #VALUE!
two FALSE #VALUE!
[blank] FALSE TRUE

 

[Mike H]

Read my reply. The ISEVEN function truncates decimals before testing for even

Mike

That solves the problem of the big numbers, but it introduces other errors.
Here are some samples:

Value MyIsEven ISEVEN
1.2 TRUE FALSE
abc2 TRUE #VALUE!
two FALSE #VALUE!
[blank] FALSE TRUE

Make the argument a string rather than a number:

Function MyIsEven(r As Range) As Boolean
Dim s As String
s = r.Value
Select Case Right(s, 1)
Case 0, 2, 4, 6, 8
MyIsEven = True
Case Else
MyIsEven = False
End Select
End Function

 

[Horatio J. Bilge, Jr.]

That works on all of my samples, except for negative decimals. I changed it to:
s = Fix(r.Value) and it seems to work great.

Thanks!

 

[Mike H]

Good point, INT rounds the 'wrong' way for your purposes

Mike

 

[Horatio J. Bilge, Jr.]

It worked great in my test workbook, but when I put in into the actual
workbook, I got an error. I think the error is because the value I am testing
is not a range.
=MyIsEven(COUNT(A1:G1)) --> gives #VALUE! error
=MyIsEven(2) --> also gives #VALUE! error