S
S Himmelrich
I'm trying to recall the vb syntax to perform the above function,
which will evaluate each row in a column that will have this type of
data:
3180015155 002075
and replace the current data with the last 6 characters like this:
002075
recommendations?
which will evaluate each row in a column that will have this type of
data:
3180015155 002075
and replace the current data with the last 6 characters like this:
002075
recommendations?