Configuring directory in which Explorer opens

[Guest]

I would like to configure Explorer so that it always opens in a certain
directory. The "New" code below will do this but also opens that directory
if I click on a directory in the left pane. This is a nuisance. I don't like
to have to click only on the directory tree in the left pane until I get to
the directory I want.

I tried leaving the %I but this made no difference.

Default:
[HKEY_CLASSES_ROOT\Folder\shell\explore\ddeexec]
@="[ExploreFolder(\"%l\", %I, %S)]"
"NoActivateHandler"=""

New:
[HKEY_CLASSES_ROOT\Folder\shell\explore\ddeexec]
@="[ExploreFolder(\"c:\\myfolder\", c:\\myfolder, %S)]"
"NoActivateHandler"=""

How can I configure Explorer so that it opens in a certain directory but
then allows clicking on any directory in either the right or left pane
without going back to that directory again until I reach the desired
directory.

John
John Wirt

 

[Guest]

Create a new shortcut, and drag it to Quicklaunch, or put it in the start
menu. The command for the Properties of the shortcut can be something like

explorer /e,/root,C\Program Files

explorer /e,/root,C:\Program Files,/select,C:\Program Files\Common Files

Command-Line Switches for Windows Explorer:
http://support.microsoft.com/kb/130510