Calling an overloaded generic method

[Peter Morris]

public void DoSomething<T>(object value)
{
<code omitted>
}

public void DoSomething<T>()
{
How do I now call this.DoSomething<T>(null);
}



Thanks


Pete

 

[Nicholas Paldino [.NET/C# MVP]]

Pete,

You will have to cast the null, like so:

this.DoSomething<T>((object) null);

 

[Peter Morris]

Ahh. I thought it *should* work. Thanks!


Pete

 

[Pavel Minaev]

public void DoSomething<T>(object value)
{
    <code omitted>

}

public void DoSomething<T>()
{
    How do I now call this.DoSomething<T>(null);

}

With the code as written, it should be just "DoSomething<T>(null)" -
there are no ambiguities here. Perhaps you've meant the first
signature to be "DoSomething<T>(T)"? Then you could either use the
cast as suggested, or explicitly specify T on call:
"DoSomething<object>(null)".

 

[Pavel Minaev]

public void DoSomething<T>(object value)
{
    <code omitted>

}

public void DoSomething<T>()
{
    How do I now call this.DoSomething<T>(null);

}

With the code as written, it should be just "DoSomething<T>(null)" -
there are no ambiguities here. Perhaps you've meant the first
signature to be "DoSomething<T>(T)"? Then you could either use the
cast as suggested, or explicitly specify T on call:
"DoSomething<object>(null)".