J
Johnnie Q
someone sent me this problem to be solved in excel, can
anyone help?
if you have 5 partners (A&1, B&2, C&3, D&4 and E&5) in how
many ways can the couples be arranged so that no partners
are together (i.e. you couldn't have A with 1 or B with 2
etc...)? presume A, B, C, D and E are all males and 1, 2,
3, 4 and 5 are all females therefore, only males and
females may couple up and A cannot go with 1, B cannot go
with 2, C cannot go with 3, D cannot go with 4 and E
cannot go with 5, how many combos?
thanks in advance
Johnnie
anyone help?
if you have 5 partners (A&1, B&2, C&3, D&4 and E&5) in how
many ways can the couples be arranged so that no partners
are together (i.e. you couldn't have A with 1 or B with 2
etc...)? presume A, B, C, D and E are all males and 1, 2,
3, 4 and 5 are all females therefore, only males and
females may couple up and A cannot go with 1, B cannot go
with 2, C cannot go with 3, D cannot go with 4 and E
cannot go with 5, how many combos?
thanks in advance
Johnnie