Bingo

D

Dee Cee

does anyone know what is the formula to produce 6 bingo
tickets containing all 90 numbers on 1 card?
 
R

Ragdyer

"Normal" Bingo cards contain 24 numbers and a free space in the middle.
Also, there are only *75 TOTAL* numbers in the Bingo matrix.
So, I don't really understand you're question, unless we're talking about a
system that isn't usually played in what can be called "Church Bingo".

If you're interested in creating something that fits my description above,
this old post may help.

http://tinyurl.com/29ma2
 
S

Sandy Mann

RD

FWIW in the UK *Bingo* has 90 numbers with 3 rows of 5 numbers in each
ticket so in 6 tickets, (1 *card*), you have all the numbers from1 to 90.

I have often mused - as an academic exercise only - if there was an
algorithm to produce sets of six tickets. Each ticket must have at least
one number from each decade with some decades having two and some three
numbers on the same ticket. There is no given layout for sets of six
tickets but I assume that there is a limited number, albeit a high number,
of possible permutations.

(For the purists *decades* is not quite correct. The first *decade* is 1 -
9 second 10 - 19 etc. with the final *decade* being actually 11 numbers from
80 - 90)

Regards

Sandy
 
R

RagDyeR

Never realized there was an American Bingo and a British Bingo.

I assume the folks "down-under" play the British form.

Wonder what type Debra and Gord play?
--

Regards,

RD
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Please keep all correspondence within the Group, so all may benefit !
--------------------------------------------------------------------

RD

FWIW in the UK *Bingo* has 90 numbers with 3 rows of 5 numbers in each
ticket so in 6 tickets, (1 *card*), you have all the numbers from1 to 90.

I have often mused - as an academic exercise only - if there was an
algorithm to produce sets of six tickets. Each ticket must have at least
one number from each decade with some decades having two and some three
numbers on the same ticket. There is no given layout for sets of six
tickets but I assume that there is a limited number, albeit a high number,
of possible permutations.

(For the purists *decades* is not quite correct. The first *decade* is 1 -
9 second 10 - 19 etc. with the final *decade* being actually 11 numbers from
80 - 90)

Regards

Sandy
 

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