AssemblyVersionAttribute

[Oleg Ogurok]

Hi all,

According to this document, the auto-generated revision number for an
assembly is the number of seconds since midnight divided by 2. I'm testing
this with my code but the revision comes out 60 minutes ahead.

http://msdn.microsoft.com/library/d...lectionassemblyversionattributeclasstopic.asp

Here's the code:

DateTime now = DateTime.Now;
DateTime jan2000 = new DateTime(2000, 1, 1);
int build = (int)now.Subtract(jan2000).TotalDays;
int revision = (int)now.Subtract(DateTime.Today).TotalSeconds / 2;
textBox1.Text += "assembly version: " +
Assembly.GetExecutingAssembly().GetName().Version.ToString() +
Environment.NewLine;
textBox1.Text += "Build: " + build + Environment.NewLine;
textBox1.Text += "Rev: " + revision + Environment.NewLine;


Here's the output:

assembly version: 1.0.1731.23390
Build: 1731
Rev: 25192

Any ideas on how to properly calculate the Revision number?
Thanks,

-Oleg.

 

[Richard Blewett [DevelopMentor]]

Is it an issue with Daylight Saving?

Regards

Richard Blewett - DevelopMentor
http://staff.develop.com/richardb/weblog

nntp://news.microsoft.com/microsoft.public.dotnet.framework/<[email protected]>

Hi all,

According to this document, the auto-generated revision number for an
assembly is the number of seconds since midnight divided by 2. I'm testing
this with my code but the revision comes out 60 minutes ahead.

http://msdn.microsoft.com/library/d...lectionassemblyversionattributeclasstopic.asp

Here's the code:

DateTime now = DateTime.Now;
DateTime jan2000 = new DateTime(2000, 1, 1);
int build = (int)now.Subtract(jan2000).TotalDays;
int revision = (int)now.Subtract(DateTime.Today).TotalSeconds / 2;
textBox1.Text += "assembly version: " +
Assembly.GetExecutingAssembly().GetName().Version.ToString() +
Environment.NewLine;
textBox1.Text += "Build: " + build + Environment.NewLine;
textBox1.Text += "Rev: " + revision + Environment.NewLine;


Here's the output:

assembly version: 1.0.1731.23390
Build: 1731
Rev: 25192

Any ideas on how to properly calculate the Revision number?
Thanks,

-Oleg.




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