adding a hard coded number to a short creates a build error

[TS]

short x = 1;
//this has build error saying missing conversion
x = x + 2;

Why can't you just add this?

I guess the 1 is a literal that translates to an int32?

How would I accomplish this statement?

 

[rossum]

short x = 1;
//this has build error saying missing conversion
x = x + 2;

Why can't you just add this?

I guess the 1 is a literal that translates to an int32?

How would I accomplish this statement?

x = (short)(x + 2);

IIRC the + operator returns an int unless either operand is a long,
float or double.

rossum

 

[Linda Liu [MSFT]]

Hi TS,

Rossum has given the right answer.

You can declare and initialize a short variable like this example:

short x = 32767;

In the preceding declaration, the integer literal 32767 is implicitly
converted from int to short. If the integer literal does not fit into a
short storage location, a compilation error will occur.

The following assignment statement will produce a compilation error,
because the arithmetic expression on the right-hand side of the assignment
operator evaluates to int by default.

short z = x + y; // Error: no conversion from int to short

To fix this problem, use a cast:

short z = (short)(x + y); // OK: explicit conversion

Hope this helps.
If you have any question, please feel free to let me know.

Sincerely,
Linda Liu
Microsoft Online Community Support

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[TS]

thanks all