Activating an instance of a class in a referenced assembly

[Scott Hodson]

I'm trying to use Type.GetType() so I can create an instance of a class I
have defined in a different, yet referenced, assembly but it doesn't seem to
be able to find the type. How can I get a type object of a class in
another assembly?

For example, if you reference the System.Xml namespace, try this
Type importType = Type.GetType("System.Xml.XmlException", true);

It will throw an exception. I see that there is also the
GetTypeFromProgID() and GetTypeFromCLSID() methods in the Type class but
these seem to only apply to registered COM objects.

 

[Wiktor Zychla]

For example, if you reference the System.Xml namespace, try this

Type importType = Type.GetType("System.Xml.XmlException", true);

this is not the full type name. try:

Type t = typeof( XmlException );
MessageBox.Show( t.AssemblyQualifiedName );

to see the full type name. you can use the full type name to get the type by
Type.GetType( "......." );


remember that whenever the type is statically known, you can use

Type t = typeof( _type_name_ );
instead of
Type t = Type.GetType( _fully_qualified_type_name );

regards,
Wiktor

 

[Scott Hodson]

No, you are incorrect. The sample code I gave you, if run, will throw an
exception. If I take out the true parameter on the call to GetType I won't
get an exception, but the reference "importType" will be null.

And I can't do this statically, I need do do this dynamically with a string.
I need a way to dynamically instantiate an instance of a class that resides
in another assembly, and GetType() is not able to find it, it seems to only
work for classes in the same assemble as the caller.