Problem removing Text from RichTextbox

[Joe Cool]

I am trying to remove some text from a RichTextbox. Let's say it
contains something like:

Line 1
Line 2

"Line 1" is bold, "Line 2" is not. If I remove "Line 1" with:

richTextbox.Text = richTextbox.Text.Replace("Line 1", "");

it removes the text "Line 1" but now Line 2 is bold!!!

How can I remove a bolded "Line 1" without "Line 2" assuming "Line
1"'s bold attribute?

 

[ZokiManas]

I've tried your example and it's truly setting Line2 in bold. Try following...
If you are selecting the text manually, use this:

string selectedText = rtb.SelectedText;

If you are selecting the text programatically, use this(as in your example):

string selectedText = "Line 1";

And use following code to remove the text:

if (selectedText.Length > 0)
rtb.SelectedText = "";
else
{
int caretPosition = rtb.SelectionStart;
if (caretPosition != rtb.TextLength)
{
rtb.Select(caretPosition, 1);
rtb.SelectedText = "";
}
}

Hope this helps.

 

[Joe Cool]

I've tried your example and it's truly setting Line2 in bold. Try following...
If you are selecting the text manually, use this:

string selectedText = rtb.SelectedText;

If you are selecting the text programatically, use this(as in your example):

string selectedText = "Line 1";

And use following code to remove the text:

if (selectedText.Length > 0)
            rtb.SelectedText = "";
            else
            {
                int caretPosition = rtb.SelectionStart;
                if (caretPosition != rtb.TextLength)
                {
                    rtb.Select(caretPosition, 1);
                    rtb.SelectedText = "";
                }
            }

Hope this helps.

Well, it helped in the sense it gave me some ideas. I was able to
accomplish this with the following code:

rtb.Find("Line 1");
rtb.Select();
rtb.SelectionLength++;
rtb.SelectedText = string.Empty;

I am bumping up the SelectionLength by one because, in my specific
case, I know that the text I will be removing will be followed by "\n"
and I want to remove it also.