A
Andrew Larder
Hi,
I'm trying to write a high performance numerical app in C#, and would like
to use operator overloading, but currently things are running a bit slower
than non op-overloaded code.
If I overload operators on a struct, lets for example say a Vector3 (3D
vector), does this mean when I write:
Vector3 a = new Vector(1,2,3);
Vector3 b = new Vector(4,5,6);
Vector3 c = new Vector(0,0,0);
c = a + b;
that 'a' and 'b' have to be boxed before they are passed to my
operator+(...) code, and the return value boxed as well?
I'm trying to write a high performance numerical app in C#, and would like
to use operator overloading, but currently things are running a bit slower
than non op-overloaded code.
If I overload operators on a struct, lets for example say a Vector3 (3D
vector), does this mean when I write:
Vector3 a = new Vector(1,2,3);
Vector3 b = new Vector(4,5,6);
Vector3 c = new Vector(0,0,0);
c = a + b;
that 'a' and 'b' have to be boxed before they are passed to my
operator+(...) code, and the return value boxed as well?