need help using "RANDBETWEEN" in excel

[glenn]

In using this function, I'm entering values as decimals (ie, I'm looking for
a random number between 1.35 and 1.65. When I do this I get a result of 2.
That's obviously not a number between 1.35 and 1.65. What am I doing wrong?

 

[Teethless mama]

=RANDBETWEEN(135,165)/100

 

[JoeU2004]

In using this function, I'm entering values as decimals
(ie, I'm looking for a random number between 1.35 and
1.65. When I do this I get a result of 2. That's obviously
not a number between 1.35 and 1.65. What am I doing
wrong?

"Obviously" impossible to say, since you neglect to show us exactly the
formula you are using and how the cells are formatted. (Klunk!)

The solution might be as simple as changing the cell format to Number with 2
decimal places.

Do that anyway. But also, you might be sure that you are using the
following formula:

=RANDBETWEEN(135,165) / 100

or something like that.

 

[Amish]

You should consider checking Help (especially for functions) next
time. Help indicates that the numbers must be integers, which explains
your invalid output.

RANDBETWEEN(bottom,top)
Bottom is the smallest integer RANDBETWEEN will return.
Top is the largest integer RANDBETWEEN will return.

Also, using More Functions (AKA Paste Function and Function Wizard)
will walk through arguments, define the properties, and show you the
result before you finish.

 

[David Biddulph]

My guess is that what you are doing wrong is not reading the Excel help for
the function which you are trying to use.

It says (inter alia):
"Returns a random integer number between the numbers you specify. A new
random integer number is returned every time the worksheet is calculated.

Syntax
RANDBETWEEN(bottom,top)

Bottom is the smallest integer RANDBETWEEN will return.

Top is the largest integer RANDBETWEEN will return."

If you are hoping to get an non-integer number as an output from
RANDBETWEEN, you'll be out of luck. Other folk have suggested how to get
round this problem.