Macro line too long?

M

MrRJ

I went to program this formula in my macro, it did not work. I am thinking
that it is too long to accept it. I even did it manually while the macro was
recording and it didn't record anything. Wonder why? The actual formula
does work, but want it to work in my macro.

Please help.
ActiveCell.FormulaR1C1 = _
"=IF(ISERROR(RC[-1]),RC[2],INDEX('[Charge Type
Translation.xls]Sheet1'!R2C1:R24C1,MAX(INDEX(('[Charge Type
Translation.xls]Sheet1'!R2C2:R24C27=RC[3])*ROW('[Charge Type
Translation.xls]Sheet1'!R2C2:R24C27),))-ROW('[Charge Type
Translation.xls]Sheet1'!R1C2))"

MrRJ
 
M

MrRJ

Hi Simon,
I am still have problems. Not sure why?
Range("P2").Select
ActiveCell.FormulaR1C1 = _
"=IF(ISERROR(RC[-1]),RC[2],INDEX" _
& "('[Charge Type Translation.xls]Sheet1'!R2C1:R24C1,MAX" _
& "(INDEX(('[Charge Type Translation.xls]Sheet1'!R2C2:R24C27=RC[3])*ROW" _
& "('[Charge Type Translation.xls]Sheet1'!R2C2:R24C27),))-ROW('[Charge
Type Translation.xls]Sheet1'!R1C2))"
Range("P2").Select

Simon Lloyd said:
Assuming your formula works, you just haven't broken it up correctly:
ActiveCell.FormulaR1C1 =
"=IF(ISERROR(RC[-1]),RC[2],INDEX" _
& "('[Charge Type Translation.xls]Sheet1'!R2C1:R24C1,MAX" _
& "(INDEX(('[Charge Type
Translation.xls]Sheet1'!R2C2:R24C27=RC[3])*ROW" _
& "('[Charge Type Translation.xls]Sheet1'!R2C2:R24C27),))-ROW('[Charge
Type Translation.xls]Sheet1'!R1C2))"

MrRJ;236034 said:
I went to program this formula in my macro, it did not work. I am
thinking
that it is too long to accept it. I even did it manually while the
macro was
recording and it didn't record anything. Wonder why? The actual formula
does work, but want it to work in my macro.

Please help.
ActiveCell.FormulaR1C1 = _
"=IF(ISERROR(RC[-1]),RC[2],INDEX('[Charge Type
Translation.xls]Sheet1'!R2C1:R24C1,MAX(INDEX(('[Charge Type
Translation.xls]Sheet1'!R2C2:R24C27=RC[3])*ROW('[Charge Type
Translation.xls]Sheet1'!R2C2:R24C27),))-ROW('[Charge Type
Translation.xls]Sheet1'!R1C2))"

MrRJ


--
Simon Lloyd

Regards,
Simon Lloyd
'The Code Cage' (http://www.thecodecage.com)
 

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