How to determine the first 6 large numbers from a list?

E

Eric

Does anyone have any suggestions on how to determine the first 6 large
numbers from a list under column A? such as
Under column A, there is a list of numbers
11,23,42,32,63,45,76,34,56,34,67,87,45,55,67,65,43,45,23,66,...
If any number in column A is the first 6 large numbers, then return 1 in B
column related to the same row.
Does anyone have any suggestions?
Thanks in advance for any suggestions
Eric
 
M

Max

One way
Assume numbers running in A1 down
Put in B1, array-enter the formula by pressing CTRL+SHIFT+ENTER:
=IF(ISNUMBER(MATCH(A1,LARGE($A$1:$A$100,{1;2;3;4;5;6}),0)),1,"")
Copy B1 down to the last row of data in col A. Adapt the range to suit.
 
S

Stefi

Enter in B1 and drag down as required:
=IF(A1<=LARGE(A:A,6),1,0)

Regards,
Stefi

„Eric†ezt írta:
 
I

iliace

Does anyone have any suggestions on how to determine the first 6 large
numbers from a list under column A? such as
Under column A, there is a list of numbers
11,23,42,32,63,45,76,34,56,34,67,87,45,55,67,65,43,45,23,66,...
If any number in column A is the first 6 large numbers, then return 1 in B
column related to the same row.
Does anyone have any suggestions?
Thanks in advance for any suggestions
Eric

You can enter this array formula in B1:B6 range:

=LARGE($A:$A,{1;2;3;4;5;6})

Replace the semicolons with columns, and you can use the same formula
in B1:G1 range:

=LARGE($A:$A,{1,2,3,4,5,6})

This depends on the list separator setting in your regional settings.
 

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