How do I create formula to calc difference in dates?

[Guest]

I have a 'hire date' & a 'term date'. I need to calcuate the difference in
months & don't want to do the calculations manually. EX. 7/1/06 1/1/06 = 6
months

 

[Guest]

dlcroswell,

If 7/1/06 is in cell a1, and 1/1/06 is in cell b2 then
in cell c1*
=MONTH(A1)-MONTH(B1)

*note, you may have to format cells to general or number

Hope this helps

---Bigpig---

 

[Mike]

=MONTH(A1)-MONTH(B1)

That works when the two months are in the same year, but what if they are in
different years? For example January 2008-September 2007 = -8, but should
equal 4. Or December 2008-January 2006 = 11, but should equal 23.

 

[Ron Rosenfeld]

=MONTH(A1)-MONTH(B1)

That works when the two months are in the same year, but what if they are in
different years? For example January 2008-September 2007 = -8, but should
equal 4. Or December 2008-January 2006 = 11, but should equal 23.

Use the undocumented DATEDIF function:

=DATEDIF(B1,A1,"m")

(The first date must be the earlier date).


See http://www.cpearson.com/Excel/datedif.aspx for documentation.

--ron

 

[David Biddulph]

I hope that Dec 2008 - Jan 2006 is 35, rather than 23.

An alternative to DATEDIF would be
=MONTH(A1)-MONTH(B1)+12*(YEAR(A1)-YEAR(B1))
Note that if you have different dates within the start and end months,
you'll get different results from the 2 formulae.
End of Jan to beginning of Feb gives a 1 month difference with the original
=MONTH(A1)-MONTH(B1) and with my extension thereto, but DATEDIF counts
completed months (with various questions when months are of unequal length).

 

[Terry Rogers]

How would you do this calculation for a range of cells all compared to the
current date but ignoring blank cells? ex: =(L25-M3) works fine (L25
contains the =today() formula to insert the current date) but where column
"N" contains no value it displays an errent number. In other words if there
is no value in column "M" I want no value returned.

 

[VSlaybaugh]

I have tried this function but am having trouble with it returning the right
value. I have an end-date of 1/20/2010 (in cell F16) and a start-date of
2/11/2009 (in cell E16). I'm trying to calculate how many automatic monthly
transfers there will be on the 20th of each month but the function is
returning a value of 11 when it should return a value of 12. The first
transfer will be 2/20/2009 and the last transfer will be 1/20/2010…a total of
12 transfers.

 

[T. Valko]

Try this:

E16 = start date
F16 = end date

=SUMPRODUCT(--(DAY(ROW(INDIRECT(E16&":"&F16)))=20))

That will count how many 20th of the months there are from a start date to
an end date (inclusive).

 

[Fred Smith]

Very impressive, Biff.

Fred

Try this:

E16 = start date
F16 = end date

=SUMPRODUCT(--(DAY(ROW(INDIRECT(E16&":"&F16)))=20))

That will count how many 20th of the months there are from a start date to
an end date (inclusive).

 

[T. Valko]

Thanks!

--
Biff
Microsoft Excel MVP

Very impressive, Biff.

Fred

 

[VSlaybaugh]

Wow! This works great. I appreciate your quick responses when I submit a
problem I'm having. You always have a solution that works. I just wish I
understood what you did to make it happen.

 

[T. Valko]

You're welcome. Thanks for the feedback!

 

[Imran ul Haque]

Can you help me in finding difference of data between 12/10/2003 &
2/14/2009. With datedif or usual cell1 - cell2 formulae it shows 1893 days
where as my manual calculation shows it to be
Year Days
2003 52
2004 360
2005 360
2006 360
2007 360
2008 360
2009 45
Total 1897

Appreciate you help.
Imran

 

[Imran ul Haque]

sorry but the actual manual calculation is as follows:

Year Days
2003 52
2004 364
2005 364
2006 365
2007 364
2008 364
2009 45
Total days 1918

 

[Fred Smith]

Imran,

First, if you have a new query, start a new thread. When you add to an
existing thread, there's too much chance it will get lost.
Second, there are 365 days in a year, not 364. In leap years, there are 366.
Third, you need to be consistent in your date formats. Because the second
date can only be Feb 14/09, the first date must be Dec 10/03, not Oct 12.

So, your actual days in between are:
2003: 21
2004: 366
2005: 365
2006: 365
2007: 365
2008: 366
2009: 45
Total: 1893

Regards,
Fred.

 

[DIPESH]

I have a 'hire date' & a 'term date'. I need to calcuate the difference in
months & don't want to do the calculations manually. EX. 7/1/06 1/1/06 = 6
months

 

[Kenneth Green]

Hi Biff

If I wanted to use a formual to count days including the start date and end
dates what would i use?

e.g days between january 1, 2009 - january 7, 2009 is seven days, but using
the formulas it gives a result of 6 instead of seven

Thanks
Ken

 

[Peo Sjoblom]

To me it is only 6 days, how do you get 7?

--


Regards,


Peo Sjoblom

 

[Dave Peterson]

You could just add one more to the result:

=a1-a2+1

 

[Bob I]

Subtracting one date from another is always going to give that result.
It's the same as subtracting one number from another. If you want
inclusive, you will have to add one back or subtract the day before the
start day.