How can I do this?

[Tmaxx02]

I have a sheet with numbers in three columns.
I would like to have a formula or function to
look across the row and tell me if there is a
consecutive number. In other words:

A B C D
3 4 1 34

In column D, I'd like display the results 34 if
there are consecutive numbers.

Thanks in advance.

 

[JE McGimpsey]

One way:

D1: =IF(B1=A1+1,A1&B1&IF(C1=B1+1,C1,""),IF(C1=B1+1,B1&C1,""))

 

[Pete_UK]

Assuming your numbers are in row 1, try this in D1:

=IF(B1=A1+1,A1&B1,IF(C1=B1+1,B1&C1,""))

Note that this returns a text answer - if you had 10 in one cell and
11 next to it you would get 1011.

Hope this helps.

Pete

 

[Tmaxx02]

Both of these work with this exception: if 4 is before the 3, it
returns a blank.
I think that I could probably work this out though. Thanks very much,
I appreciate it.

Terry

 

[T. Valko]

This accounts for both ascending and descending values:

A B C D
3 4 1 34
4 3 1 43

=IF(ABS(A1-B1)=1,A1&B1&IF(ABS(B1-C1)=1,C1,""),IF(ABS(B1-C1)=1,B1&C1,""))

Biff

 

[Tmaxx02]

This accounts for both ascending and descending values:


=IF(ABS(A1-B1)=1,A1&B1&IF(ABS(B1-C1)=1,C1,""),IF(ABS(B1-C1)=1,B1&C1,""))

Biff

That worked great. It also accounted for more than 2 numbers. Thanks
very much.

Terry

 

[T. Valko]

Note the result if the values are negative:

A B C D
-3 -4 1 -3-4

Biff

 

[T. Valko]

That worked great. It also accounted for more than 2 numbers. Thanks
very much.

Terry

You're welcome. Thanks for the feedback!

Biff