converting VB6 to vb.net

[Brian]

for some reason I can not get this to work.. but there is something
different about it...
OffSet in both peices = 4812
VB 6 CODE:
Const Sch As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZab"
ShiftCode = Mid$(Sch, (OffSet Mod 28) + 1, 1)

this function returns RYDK which is correct..

VB.Net 2005 Code:
Const Sch As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZab"

Return Sch.Substring((OffSet Mod 28) + 1, 1)

returns SZEL

Why is there a differance? what am i missing?

 

[Stephany Young]

The index (first parameter) for the String.SubString() method is zero based,
so it should be:

Return Sch.Substring(OffSet Mod 28, 1)

 

[Bill McCarthy]

for some reason I can not get this to work.. but there is something
different about it...
OffSet in both peices = 4812
VB 6 CODE:
Const Sch As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZab"
ShiftCode = Mid$(Sch, (OffSet Mod 28) + 1, 1)

this function returns RYDK which is correct..

Really ? Here it returns Y which is what I would expect.

VB.Net 2005 Code:
Const Sch As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZab"

Return Sch.Substring((OffSet Mod 28) + 1, 1)

returns SZEL

Why is there a differance? what am i missing?

Well considering both Mid and SubString with the last parameter as 1 only
return a single character, I'd say you are missing code that does as you
described in either VB6 or Vb.NEt

 

[Brian]

That seems to be it.. thanks

The index (first parameter) for the String.SubString() method is zero
based, so it should be:

Return Sch.Substring(OffSet Mod 28, 1)