Check Box

[alpine7411]

I have a spreadsheet set up where you would check a check box and a
value will pop into a cell on another sheet. If you uncheck it the
value will disappear. I keep getting an error that says "Identifier
under cursor is not recognized". Its in the line where it selects a
range of cells. What i'm I missing here?

Private Sub CheckBox1_Click()

With CheckBox1
If .Value = True Then
Sheets("RENOVATION").Select
Range("B6:E6").Select
ActiveCell.FormulaR1C1 = "Leased"
Sheets("COVER").Select
Else
Sheets("RENOVATION").Select
Range("B6:E6").Select
Selection.ClearContents
Sheets("COVER").Select

End If
End With
End Sub

 

[Dave Peterson]

I don't know. What is the under the cursor?

But I'd drop the selecting:

Option Explicit
Private Sub CheckBox1_Click()
With CheckBox1
If .Value = True Then
Worksheets("RENOVATION").Range("B6:E6").Value = "Leased"
Else
Worksheets("RENOVATION").Range("B6:E6").ClearContents
End If
End With
End Sub

 

[alpine7411]

I don't know. What is the under the cursor?

But I'd drop the selecting:

Option Explicit
Private Sub CheckBox1_Click()
With CheckBox1
If .Value = True Then
Worksheets("RENOVATION").Range("B6:E6").Value = "Leased"
Else
Worksheets("RENOVATION").Range("B6:E6").ClearContents
End If
End With
End Sub










--

Dave Peterson- Hide quoted text -

- Show quoted text -

Dave,

I'm not sure what the "under the cursor" is either. But the code you
provided help out a lot.

Thanks,
Keith

 

[Guest]

This should correct the problem
Private Sub CheckBox1_Click()

With CheckBox1
If .Value = True Then
Sheets("RENOVATION").Select
Range("B6:E6").FormulaR1C1 = "Leased"
Sheets("COVER").Select
Else
Sheets("RENOVATION").Select
Range("B6:E6").ClearContents
Sheets("COVER").Select

End If
End With

End Sub
You don't need to select the ranges.

If this posting was helpful, please click on the Yes button.
Regards,

Michael Arch.