using Type

[Jinsong Liu]

I have a function, which accept two parameters, one is a object,
another is a Type. I need to cast the object to the type define by
Type. is it possible?

void MyFunction(Object O, Type T)
{
// this is what I want to do
T MyObject=(T)O;
}

 

[Nicholas Paldino [.NET/C# MVP]]

Jinsong,

You can't do this without Generics, you could do something like this:

void MyFunction<T>(object o)
{
T MyObject = (T) o;
}

However, that's kind of pointless, because you could just do this then:

void MyFunction<T>(T o)
{
// Use o here as T.
}

This is better, since it will throw a compiler error if the object you
pass is not of type T (or derived from T).

In .NET 1.1 you should define a common interface that the instances
implement and then make your parameter that.

Hope this helps.

 

[Ignacio Machin \( .NET/ C# MVP \)]

Hi,

No, you cannot do that.

What is what you want to do?

You could use reflection to call members of T though.

 

[Obinna]

Nicholas Paldino, why wont this work?

String strA;
int i = (int) strA;

// gives the error can't cast string to integer (or something like
that)

Obinna.

Jinsong,

You can't do this without Generics, you could do something like this:

void MyFunction<T>(object o)
{
T MyObject = (T) o;
}

However, that's kind of pointless, because you could just do this then:

void MyFunction<T>(T o)
{
// Use o here as T.
}

This is better, since it will throw a compiler error if the object you
pass is not of type T (or derived from T).

In .NET 1.1 you should define a common interface that the instances
implement and then make your parameter that.

Hope this helps.


--
- Nicholas Paldino [.NET/C# MVP]
- (e-mail address removed)

I have a function, which accept two parameters, one is a object,
another is a Type. I need to cast the object to the type define by
Type. is it possible?

void MyFunction(Object O, Type T)
{
// this is what I want to do
T MyObject=(T)O;
}