(urgent) Binary data to byte[] array

[Guest]

Hi,

I have the following binary data:

0x800006000000

which is equivalent to the followin

byte[] bytes = new byte[6];
bytes[0] = 0x80;
bytes[1] = 0x00;
bytes[2] = 0x06;
bytes[3] = 0x00;
bytes[4] = 0x00;
bytes[5] = 0x00;

How can I parse the binary to the quivalent byte array?

Thanks,

Yama

 

[Jon Skeet [C# MVP]]

I have the following binary data:

0x800006000000

As what?

which is equivalent to the followin

byte[] bytes = new byte[6];
bytes[0] = 0x80;
bytes[1] = 0x00;
bytes[2] = 0x06;
bytes[3] = 0x00;
bytes[4] = 0x00;
bytes[5] = 0x00;

How can I parse the binary to the quivalent byte array?

It would help if you could give more details. When you say you have the
data, what format do you have it in? A long? A string?

 

[Guest]

800006000000 = string

I have the following binary data:

0x800006000000

As what?

which is equivalent to the followin

byte[] bytes = new byte[6];
bytes[0] = 0x80;
bytes[1] = 0x00;
bytes[2] = 0x06;
bytes[3] = 0x00;
bytes[4] = 0x00;
bytes[5] = 0x00;

How can I parse the binary to the quivalent byte array?

It would help if you could give more details. When you say you have the
data, what format do you have it in? A long? A string?

 

[Guest]

800006000000 = string

I have the following binary data:

0x800006000000

As what?

which is equivalent to the followin

byte[] bytes = new byte[6];
bytes[0] = 0x80;
bytes[1] = 0x00;
bytes[2] = 0x06;
bytes[3] = 0x00;
bytes[4] = 0x00;
bytes[5] = 0x00;

How can I parse the binary to the quivalent byte array?

It would help if you could give more details. When you say you have the
data, what format do you have it in? A long? A string?

 

[Hung Huynh]

Hi,

I have the following binary data:

0x800006000000

which is equivalent to the followin

byte[] bytes = new byte[6];
bytes[0] = 0x80;
bytes[1] = 0x00;
bytes[2] = 0x06;
bytes[3] = 0x00;
bytes[4] = 0x00;
bytes[5] = 0x00;

How can I parse the binary to the quivalent byte array?

Thanks,

Yama

String s = "800006000000";
long n = Int64.Parse(s);

byte[] a = new byte[8];
int s, i;
for (i = 0, s = 56; i < 8; i++, s -= 8)
a = (byte)(0xFF & (n >> s));