Type mismatch error

  • Thread starter Thread starter Gautam
  • Start date Start date
G

Gautam

When i try the following statement in a macro, i get an error 13, Type
mismatch. Could anyone solve this please
ActiveSheet.Cells(j, colcount) = (data(j, i)) / 587

array data is declared as variant

Thanks
 
Hi
data should be an array e.g.

Dim data(1 to 10, 1 to 10) as double

Sometimes you need to pass arrays as variants (e.g. when trying to
copy an array to a range on a worksheet). Then you would do

Dim Variant_data as Variant
Variant_data = data

and you can access the numbers in Variant_data exactly as if it is an
array. But you MUST create data as an array FIRST and then make your
variant.

regards
Paul
 
the statement was not giving me an error. Tried a couple of ways of ways to
get errror 13. the only way I found of getting error 13 was to declare data
as a string
Dim data(10,10) as string.

Check the declaration of the array data.
 
Check your other post.
When i try the following statement in a macro, i get an error 13, Type
mismatch. Could anyone solve this please
ActiveSheet.Cells(j, colcount) = (data(j, i)) / 587

array data is declared as variant

Thanks
 
the statement was not giving me an error. Tried a couple of ways of ways to
get errror 13. the only way I found of getting error 13 was to declare data
as a string
Dim data(10,10) as string.

Check the declaration of the array data.







- Show quoted text -

Thanks Joel
The first part of the array was indeed a string
 
Hi
data should be an array e.g.

Dim data(1 to 10, 1 to 10) as double

Sometimes you need to pass arrays as variants (e.g. when trying to
copy an array to a range on a worksheet). Then you would do

Dim Variant_data as Variant
Variant_data = data

and you can access the numbers in Variant_data exactly as if it is an
array. But you MUST create data as an array FIRST and then make your
variant.

regards
Paul





- Show quoted text -

Thanks Paul
The first part of the array was a string which popped an error
the other part of the code is fine
 
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