this() vs base()

[Flip]

I'm reading in an article suggested by someone on one of the newsgroups here
(http://www.25hoursaday.com/CsharpVsJava.html) and under the topic titled
"Calling Base Class Constructors and Constructor Chaining" in the C#
example, they use the base() and this() constructors. Am I correct in
saying, the this() is the constructor chaining and the base() is like the
super() in java?

Thanks.

 

[Nicholas Paldino [.NET/C# MVP]]

Flip,

Yes, you are right. However, the restriction in .NET is that the base
constructor must be called before any code is executed in the derived
class's constructor (I believe that super can be called anywhere in the
constructor in java).

Hope this helps.

 

[Flip]

Thanks again Nicholas! :>

 

[Richard Blewett [DevelopMentor]]

this() is for constructor chaining as you say. base() is for stating how a base class constructor other than it's default constructor should be called - I have no idea whether this equates to super() in Java

Regards

Richard Blewett - DevelopMentor
http://staff.develop.com/richardb/weblog

nntp://news.microsoft.com/microsoft.public.dotnet.languages.csharp/<[email protected]>

I'm reading in an article suggested by someone on one of the newsgroups here
(http://www.25hoursaday.com/CsharpVsJava.html) and under the topic titled
"Calling Base Class Constructors and Constructor Chaining" in the C#
example, they use the base() and this() constructors. Am I correct in
saying, the this() is the constructor chaining and the base() is like the
super() in java?

Thanks.



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[microsoft.public.dotnet.languages.csharp]

 

[Jon Skeet [C# MVP]]

Yes, you are right. However, the restriction in .NET is that the base
constructor must be called before any code is executed in the derived
class's constructor (I believe that super can be called anywhere in the
constructor in java).

Nope, the rules are very similar in Java - super() or this() has to be
the first statement in a constructor.