String variable strange behavior

  • Thread starter Thread starter Tamir Khason
  • Start date Start date
T

Tamir Khason

I have some string in variable str_tmp = "C:\TMP\"
I want to display it in textbox (@-quoted), so I'm using tbx.Text =
@str_tmp; but for some strange reason this does not work. it processes
escape sequence. What is the problem???
 
Hi,

You are using incorrectly the escape char, use it when you declare your
var:
string srt_tmp = @"c:\tmp";
you don't have to use it when you assign it:
tbx.Text = @str_tmp;
you just do
tbx.Text = str_tmp;


Cheers,
 
Tamir Khason said:
Now where should I add @ in order to be able to
recieve @-quoted strings eg.
SomeStringStruct a = new SomeStringStruct ("\n\n\n")
Console.WriteLine(a.A_String); // Should return \n\n\n
and not <CR><CR><CR>
Click to expand...

@ is only useful for literal hard-coded strings in your source code.

If you want to convert non-printable characters to the text
representation of their escape sequences (e.g. <CR> to '\n'), you will
have to do the replacements yourself, e.g.

string s2 = s1.Replace("\n", @"\n"); // ... and so on

P.
 
Do not helps.
I have a struct like:

public struct SomeStringStruct
{
public string A_String;
public SomeStringStruct(string a_string)
{
A_String = a_string;
}
}
Now where should I add @ in order to be able to recieve @-quoted strings eg.
SomeStringStruct a = new SomeStringStruct ("\n\n\n")
Console.WriteLine(a.A_String); // Should return \n\n\n and not <CR><CR><CR>
 
Tamir Khason said:
Do not helps.
I have a struct like:

public struct SomeStringStruct
{
public string A_String;
public SomeStringStruct(string a_string)
{
A_String = a_string;
}
}
Now where should I add @ in order to be able to recieve @-quoted strings eg.
SomeStringStruct a = new SomeStringStruct ("\n\n\n")
Console.WriteLine(a.A_String); // Should return \n\n\n and not <CR><CR><CR>
Click to expand...

@ is only applicable to string literals in C# code itself. It affects
how the C# compiler "sees" a string literal, not how the string itself
is then processed.

If you want a string containing carriage returns to be displayed using
"\n" itself, you can do something like:

string replaced = original.Replace("\n", "\\n");
 
But I want to be able to replace all \{} sequences eg. \q\n\t etc. Is there
smart way to do it?

--
Tamir Khason
You want dot.NET? Just ask:
"Please, www.dotnet.us "
 
Would string.Replace( "\\", "\\\\" ) work?

Tamir Khason said:
But I want to be able to replace all \{} sequences eg. \q\n\t etc. Is there
smart way to do it?

--
Tamir Khason
You want dot.NET? Just ask:
"Please, www.dotnet.us "
Click to expand...
 
Nothing, even regex can not detect that \t (\n) is just "\t" but not <TAB>
I tried even Replace(((char)92).ToString(),"DUMMY"); and
..Split(new char[]{(char)92}); // This return 1 member (the whole string)



WHAT TO DO???


--
Tamir Khason
You want dot.NET? Just ask:
"Please, www.dotnet.us "


Bill O'Neill said:
Oops, I guess I oversimplified your issue...need more coffee, sorry. Try
Click to expand...
regex to replace specific tokens.
 
Tamir Khason said:
But I want to be able to replace all \{} sequences eg. \q\n\t etc. Is
there smart way to do it?
Click to expand...

Well, there are slow ways and fast ways - but I don't know of any
*particularly* great way. As ever with string manipulation, you can
approach it from various angles. Some things you might want to think
about:

o Using a StringBuilder is likely to be a good idea
o Appending whole chunks of text which don't need escaping is likely
to help
o Creating the StringBuilder to be an appropriate size to start with
will help
o Check to see if your string actually contains anything which needs
escaping before you do anything - you might want to count the number
of escapes, which allows you to create a StringBuilder of *exactly*
the right size
o It's probably worth making the routine flexible so you can easily
specify different things to escape
 
Hi Tamir,

First of all, I would like to confirm my understanding of your issue. From
your description, I understand that you need to know how to pass strings
using @-quoted strings. If there is any misunderstanding, please feel free
to let me know.

Based on my knowledge, when you pass string parameters like the following:

SomeStringStruct a = new SomeStringStruct ("\n\n\n")

The "\n\n\n" are converted to <CR><CR><CR> immediately before assigning to
A_String. @ can only be added before quotes to indicate that all the
characters in the quotes are a part of the string and the string doesn't
contain escape characters. So if you need to display \n\n\n, the only way
is to use the following:

SomeStringStruct a = new SomeStringStruct (@"\n\n\n")

HTH.

Kevin Yu
=======
"This posting is provided "AS IS" with no warranties, and confers no
rights."
 
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