Retrieving Year and calculating difference

[RP]

I have a date entered in a TextBox. On this TextBox LostFocus, I want
to retrieve the year part and then calculate the difference from
current year.

 

[Guest]

You do not need to "retrieve the year part". If both are DateTime object, all
you need to do is date math with them and get the result.
-- Peter
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[RP]

Did something like this:

 

[Peter Duniho]

Did something like this:

--------------------------------------------------------------------
DateTime myDate = txtDOB.Text;
int myYear = myDate.Year;
int PresentYear = DateTime.Now.Year;
txtAge.Text = (PresentYear - myYear);

What about the code doesn't do what you want?

The one thing that jumps out to me is that if you are really looking for
a calculation of "age", then the above doesn't take into account the
rest of the date. Is that your concern?

If so, then something like this might work for you:

DateTime myDate = DateTime.Parse(txtDOB.Text),
dateNow = DateTime.Now;
int cyearsAge = dateNow.Year - myDate.Year;

myDate = myDate.AddYears(cyearsAge);
if (myDate > dateNow)
{
cyearsAge--;
}

txtAge.Text = cyearsAge.ToString();

Pete

 

[Rad [Visual C# MVP]]

Did something like this:

--------------------------------------------------------------------
DateTime myDate = txtDOB.Text;
int myYear = myDate.Year;
int PresentYear = DateTime.Now.Year;
txtAge.Text = (PresentYear - myYear);

Of course it depends on your definition for a year. How will the code
handle a situation like 1 Jan 2007 and 31 Dec 2007? Personally I'd do
the following:

DateTime myDate = DateTime.Parse(txtDOB.Text);
TimeSpan interval = myDate - DateTime.Now
decimal years = interval.Days / 365

In this case years will have a pretty good representation of elasped
years, which you can then decide to round up depending on the level of
accuracy you want. So 0.999 could be pushed up to 1.