Result of date as Month-2 digit Year

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Guest

I have columns of dates that the users must enter as actual dates. I can
format to display month and two-digit year...but when creating pivot tables
it reconizes the entire date. Since I want to summarize only by month and
year or by year only, is there a formula or statement that will change the
date to month-year or year status only?

Thanks.
 
Hi Linda

Sure. Rightclick the date field header in the Pivot table, choose menu
"Group and show detail" > "Group"... . You will get a list offering Seconds,
minutes, hours, days, months, quarters, years. Try selecting months,
quarters and years and see what happens.

Re your other post; Try the Group menu also for other data types, it can
create some amazing summaries.

HTH. Best wishes Harald
 
Thanks Harald...I did try that and the result for date and all other field
headers in the pivot table was....Can Not Group by that Field.

However, I did find that by selecting the rows of the pivot table results
that I want grouped and following the steps you also listed, that they will
group with a title of group 1, group 2 ect. Then it is just a matter of
changing that resulting title to...in my date question of the month-year or
year.

Probably not the best solution...but it works.

Linda

Harald Staff said:
Hi Linda

Sure. Rightclick the date field header in the Pivot table, choose menu
"Group and show detail" > "Group"... . You will get a list offering Seconds,
minutes, hours, days, months, quarters, years. Try selecting months,
quarters and years and see what happens.

Re your other post; Try the Group menu also for other data types, it can
create some amazing summaries.

HTH. Best wishes Harald
 
Hi Linda

Very very strange. You should test it on a new, small file so that you can
see what it's supposed to do and maybe spot the error from there:

Enter a date in A2 and a number in B2. Fill down 100 rows or so. Add
headers in Row 1, make a pivot table with the dates as row source and group
by the it as described.

Best wishes Harald
 
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