Repost: batch files and c#

[Guest]

I have a simple .bat file (TESTMAIN.bat):
"C:\fo.bat" -xml "C:\07.xml" -xsl "C:\fo.xsl" "c:\output.pdf"

I call this using C#:
System.Diagnostics.Process p = new System.Diagnostics.Process();
p.StartInfo.FileName =@"c:\TESTMAIN.bat";

But I want to remove the hardcoded parameters ("C:\07.xml" and "C:\fo.xsl")
from TESTMAIN.bat file.

So i modify the .bat file as (is it correct??):
"C:\fo.bat" -xml %1 -xsl %2 "c:\output.pdf"

Now how do i call/replace these parameters in C#
p.StartInfo.Arguments= ??

Any pointers on how to do this?

 

[Nicholas Paldino [.NET/C# MVP]]

Gaurav,

I believe that you want to set the Arguments property to:

"\"C:\\07.xml\" \"C:\\fo.xsl\""

Hope this helps.

 

[Guest]

Works like a charm!
Thanks a bunch for your help...

Gaurav,

I believe that you want to set the Arguments property to:

"\"C:\\07.xml\" \"C:\\fo.xsl\""

Hope this helps.


--
- Nicholas Paldino [.NET/C# MVP]
- (e-mail address removed)

I have a simple .bat file (TESTMAIN.bat):
"C:\fo.bat" -xml "C:\07.xml" -xsl "C:\fo.xsl" "c:\output.pdf"

I call this using C#:
System.Diagnostics.Process p = new System.Diagnostics.Process();
p.StartInfo.FileName =@"c:\TESTMAIN.bat";

But I want to remove the hardcoded parameters ("C:\07.xml" and
"C:\fo.xsl")
from TESTMAIN.bat file.

So i modify the .bat file as (is it correct??):
"C:\fo.bat" -xml %1 -xsl %2 "c:\output.pdf"

Now how do i call/replace these parameters in C#
p.StartInfo.Arguments= ??

Any pointers on how to do this?

 

[Ignacio Machin \( .NET/ C# MVP \)]

Hi,


Does this solve your problem:

p.StartInfo.Arguments = String.Format( " -xml {0} -xls {1} {2}" , new
object[] { @"C:\07.xml" , @"C:\fo.xsl", @"c:\output.pdf"} )

I think it does