Regular express question

[Guest]

I have the following words, and I want to extract the first part and the
trailing numbers.

OP001 => ABC, 001
ST02 => CD, 02
00A => 00A, null

I have the following regular express:
(?<first>.*?)(?<second>\d+)
This one works well for the given first two examples but not the third one.

And (?<first>.*?)(?<second>\d+)$ returns strange result.

 

[Brandon Gano]

I'm unfamiliar with the <first> <second> syntax you're using, but the
following regular expression works for the three samples given:

Regex.Replace("OP001", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "OP, 001"
Regex.Replace("ST02", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "CD, 02"
Regex.Replace("00A", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "00A, "

 

[Guest]

I am using match.Groups.

I'm unfamiliar with the <first> <second> syntax you're using, but the
following regular expression works for the three samples given:

Regex.Replace("OP001", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "OP, 001"
Regex.Replace("ST02", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "CD, 02"
Regex.Replace("00A", @"(.*\D+)(\d*)", @"$1, $2"); // Returns: "00A, "

 

[Guest]

Yes, it works. Thanks.

However, there is another match, for a number

123 => 123, null

how to add this one to the regular express?

 

[Guest]

Sorry, should be

123 => null, 123

Yes, it works. Thanks.

However, there is another match, for a number

123 => 123, null

how to add this one to the regular express?

 

[Brandon Gano]

Try something like this (not tested):

(.*\D+)?(\d*)