problem with AddRange and Combobox

[Sam]

Hi,
I don't know how to specify the display and value field for a combobox
when using AddRange to fill the combo.
Here is what I have so far:


-A function to build an array of object :


Dim returnData() As Object


Do While myReader.Read()
ReDim Preserve returnData(count)
Dim currentData As New DataRecord
currentData.Display = myReader.GetValue(0).ToString


If ValueField Then
currentData.Value = myReader.GetValue(1)
End If
returnData(count) = currentData
count += 1
Loop


Return returnData


______________________________­___________________


-A function that calls the above and fills my combo


cboHeaderType.Items.AddRange(m­_queries.GetGetIdentTypes())


______________________________­____________________


The problem is that apparentely the display and value specified above
don't work and no value is selected in my combobox.


Can you help
Thx


Reply

 

[Cor Ligthert [MVP]]

Sam,

You cannot add a value to a value in the combobox.

It has to be a property from an Icollection implementing collection.

I hope this helps,

Cor

 

[Sam]

Cor,

You cannot add a value to a value in the combobox.

What do you mean ?

It has to be a property from an Icollection implementing collection

Could you give me a short example please ?

Thx

 

[Cor Ligthert [MVP]]

Sam

Roughly written here

\\\
dim dt as new datatable
dt.columns("display")
dt.columns("value")
dt.loadrow(object() {sam},true)
mycombobox.datasource = dt
mycombobox.displaymember = "display"
mycombobox.valuemember = "value"
///

Or any other icollection implementing collection.

http://msdn.microsoft.com/library/d...lrfsystemcollectionsicollectionclasstopic.asp

I hope this helps,

Cor

 

[Sam]

Thanks. This does not use AddRange. My function returns an array of
object as mentionned above. Is it not possible ?

 

[Cor Ligthert [MVP]]

Sam,

For that are in fact as well a lot of methods, to get the value is a little
bit harder than with a datasource.

An old sample Herfried showed a (long) while ago

http://www.google.de/[email protected]

I hope this helps,

Cor