Open or switch to a file

  • Thread starter Thread starter Leanne M (Aussie)
  • Start date Start date
L

Leanne M (Aussie)

Hi,

I have code to open a file in a command button which works fine.

What I would like to do is allow this button to also switch to this file if
it is already open.

I do not know how to write this so detailed help would be apprecitated.

This is the code I have for opening the file.

Private Sub CommandButton3_Click()
ChDir "C:\My Documents\Pest Control Management System"
Workbooks.Open Filename:= _
"C:\My Documents\Pest Control Management System\Pest Control
Reporting Tool.xls"
End Sub
 
Hi Leanne:

Hyperlink will open the file if it is not open and activate the file if it
is open:

Sub button_it()
s = "file:///c:\Documents and Settings\Owner\Desktop\sample.xls"
ActiveWorkbook.FollowHyperlink Address:=s
End Sub
 
Hi Gary,

Thanks that does just what I want.

I can live with it but every time I use it the Web toolbar is activated.
Any ideas why?

Leanne
 
I am not sure why this happens. Sometimes it is convenient to use the large
hyperlink arrows to move back and forth between workbooks ??
 
Oh well, I am sure some of the users will look at it and think something
major has happened but they will just have to live with it.

Thanks again
 
Actually, the Recorder worked this time:

Sub Macro1()
'
' Macro1 Macro
' Macro recorded 4/30/2008 by James Ravenswood
'

'
Application.CommandBars("Web").Visible = False
End Sub
 
I was just about to say that I recorded a macro and gave that a try but I see
you have done the exact same.

Thanks
 
Hi Leanne,

As an alternative to the suggestion of
Gary's Student, try:

'==========>>
Private Sub CommandButton3_Click()
Dim WB As Workbook
Dim myFolder As String
Dim myDrive As String
Dim sStr As String
Const sFolder As String = _
"C:\My Documents\Pest Control Management System"
Const sFile As String = "Pest Control Reporting Tool.xls"

On Error Resume Next
Set WB = Workbooks(sFile)
On Error GoTo 0

If WB Is Nothing Then
myFolder = CurDir
myDrive = CurDir
Set WB = Workbooks.Open(Filename:=sFolder _
& Application.PathSeparator _
& sFile)
ChDrive sFolder
ChDir sFolder
End If

End Sub
'<<==========
 
Hi Leanne,

Correcting the path and folder assignments,
the code should have read:

'==========>>
Private Sub CommandButton3_Click()
Dim WB As Workbook
Dim myFolder As String
Dim myDrive As String
Dim sStr As String
Const sFolder As String = _
"C:\My Documents\Pest Control Management System"
Const sFile As String = "Pest Control Reporting Tool.xls"

On Error Resume Next
Set WB = Workbooks(sFile)
On Error GoTo 0

If WB Is Nothing Then
myFolder = CurDir
myDrive = CurDir

ChDrive sFolder
ChDir sFolder
Set WB = Workbooks.Open( _
Filename:=sFolder _
& Application.PathSeparator _
& sFile)
ChDrive myFolder
ChDir myFolder
Else
WB.Activate
End If
End Sub
'<<==========
 

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