Message Queue Question:

  • Thread starter Thread starter Charles Shao
  • Start date Start date
C

Charles Shao

Message Queue Question:

I'm trying to make a demo for MSMQ.
I send a message(string) on client and try to receive it in a daemon(Windows
service).
Now, I get a problem:

1. When I start the service in services manager, The start event will be
time out. but in fact, the service is running and in loop "for".
What can I to for this problem.

Thanks

Charles Shao :-)

================================================================
server.OnStart()
{
.....
for(;;)
{
crrMsg = Msmq1.Receive();
GlobalLog.write("Received Message:" + crrMsg.Body.ToString() + "\n" );
}
}// In fact, On start will never return .
 
Charles Shao said:
Message Queue Question:

I'm trying to make a demo for MSMQ.
I send a message(string) on client and try to receive it in a
daemon(Windows
service).
Now, I get a problem:

1. When I start the service in services manager, The start event will be
time out. but in fact, the service is running and in loop "for".
What can I to for this problem.

Thanks

Charles Shao :-)

================================================================
server.OnStart()
{
.....
for(;;)
{
crrMsg = Msmq1.Receive();
GlobalLog.write("Received Message:" + crrMsg.Body.ToString() + "\n" );
}
}// In fact, On start will never return .
Click to expand...

The problem is that you need to return from OnStart within 30 seconds by
default.
So you need to spawn another thread to do the actual processing.

Willy.
 
Back
Top