Q
QuantDev
Any idea on how I can check if the variant contains an array,
considered IsArray returns true for ranges?
thanks
considered IsArray returns true for ranges?
thanks
Any idea on how I can check if the variant contains an array,
considered IsArray returns true for ranges?
Jake Marx said:Hi QuantDev,
Any idea on how I can check if the variant contains an array,
considered IsArray returns true for ranges?
If the variable is truly a Variant, then it cannot contain a reference to a
Range object. When you do this:
Dim v As Variant
v = Range("A1:A10")
The variable v is being filled with the *values* from the range A1:A10. So
the IsArray function is correct - the Variant v really does contain an array
at that point.
Maybe I'm not understanding your issue - what is it you are trying to
accomplish?
--
Regards,
Jake Marx
MS MVP - Excel
www.longhead.com
[please keep replies in the newsgroup - email address unmonitored]
Tom said:Dim v as Variant
set v = Range("A1:A10")
v will hold a range reference.
I assume he has a generalized function that is passed in a variant
which may contain a range. This would be a common need in handling
a parmarray
Jake Marx said:Hi QuantDev,
Any idea on how I can check if the variant contains an array,
considered IsArray returns true for ranges?
If the variable is truly a Variant, then it cannot contain a
reference to a Range object. When you do this:
Dim v As Variant
v = Range("A1:A10")
The variable v is being filled with the *values* from the range
A1:A10. So the IsArray function is correct - the Variant v really
does contain an array at that point.
Maybe I'm not understanding your issue - what is it you are trying to
accomplish?
--
Regards,
Jake Marx
MS MVP - Excel
www.longhead.com
[please keep replies in the newsgroup - email address unmonitored]
Stan Scott said:Function TestArray(a)
TestArray = True
On Error Resume Next
If IsError(UBound(a)) Then
TestArray = False
End If
End Function
Tom Ogilvy said:Check for a range first
if typename(varr) is "Range" then
' it's a range
elseif isarray(varr) then
' it's an array
--
Jake Marx said:Thanks for the correction, Tom. I guess I typically use variables of type
Object to do that, so I wasn't even aware (or forgot) you could do the same
thing with a Variant.
QuantDev said:"Tom Ogilvy" <[email protected]> wrote in message
Thanks Tom.
As far as you know, am I going to get "true" for isarray for others
variant/object/* combinations?
thx