V
vooose
Suppose you call
this.Invoke(new MyDelegate(MyMethod));
this.Invoke(new MyDelegate(MyMethod2));
(assume not calling from owning thread so marshall occurs)
Is MyMethod *guaranteed* to finish execution before MyMethod2 starts?
Regards
this.Invoke(new MyDelegate(MyMethod));
this.Invoke(new MyDelegate(MyMethod2));
(assume not calling from owning thread so marshall occurs)
Is MyMethod *guaranteed* to finish execution before MyMethod2 starts?
Regards