IF/Then "printable character" KeyPress

[Keith Smith]

How can I say "If e is equal to a printable character (as opposed to Insert,
Del, Home, PageUp, PageDown, etc) then x=1"?

Something like...

if (e.KeyChar==PrintableCharacters)
{
x=1;
}

 

[Guest]

if (e.KeyChar=='Q')

 

[Keith Smith]

if (e.KeyChar=='Q')

Is this the only way?

if (e.KeyChar=='A' or e.KeyChar=='a'; e.KeyChar=='B'; e.KeyChar=='b';
.....etc

If so then what a pain!

 

[Joakim Karlsson]

Keith,

Check out the static Char.IsControl method.

Regards,
Joakim

 

[Sean Hederman]

Assuming that's what you needed to do, it'd be far simpler to write:
if((e.KeyChar >= 'A' && e.KeyChar <= 'Z')) || (e.KeyChar >= 'a' && e.KeyChar
<= 'z') ...)

But I think using if(!e.KeyChar.IsControl()) as suggested by Joakim would
probably fit your needs.

 

[Keith Smith]

great idea thanks.

Assuming that's what you needed to do, it'd be far simpler to write:
if((e.KeyChar >= 'A' && e.KeyChar <= 'Z')) || (e.KeyChar >= 'a' &&
e.KeyChar <= 'z') ...)

But I think using if(!e.KeyChar.IsControl()) as suggested by Joakim would
probably fit your needs.

 

[René]

How can I say "If e is equal to a printable character (as opposed to

Insert, Del, Home, PageUp, PageDown, etc) then x=1"?

Something like...

if (e.KeyChar==PrintableCharacters)
{
x=1;
}

You could get the ascii-code for the char, and then check if it's within at
printable range ?

/René