S
Sam Carl
We have (Windows 2000 Servers and Windows 2000 Professionals desktop)
network.
Requirement is if the specified user (UserId = UserId1) logged in to our
network by logging into his/her workstation (Windows 200 professional) using
Userid = UserId1, I want to allow them to launch and query my application
(either vb.net or asp.net application) without logging onto my application.
Q1. How to do that using VB.Net application? How much programming effort is
required to read the logged in user Id when the vb.net application is
launched? Is there any alternative solution for this problem?
My approach will be, I will read the user Id who logged into the windows
2000 and then I will compare whether that user ID is allowed to launch the
application or not in the database where I will be maintaining the user
information.
Q2. Is it possible to do the same thing as specified in Q1 using ASP.Net
application? How much programming effort is required to read the user
information of the browsing computer? Is it possible? I am using IIS 5.0 and
IE 5.5+.
Thanks,
Sam Carl
network.
Requirement is if the specified user (UserId = UserId1) logged in to our
network by logging into his/her workstation (Windows 200 professional) using
Userid = UserId1, I want to allow them to launch and query my application
(either vb.net or asp.net application) without logging onto my application.
Q1. How to do that using VB.Net application? How much programming effort is
required to read the logged in user Id when the vb.net application is
launched? Is there any alternative solution for this problem?
My approach will be, I will read the user Id who logged into the windows
2000 and then I will compare whether that user ID is allowed to launch the
application or not in the database where I will be maintaining the user
information.
Q2. Is it possible to do the same thing as specified in Q1 using ASP.Net
application? How much programming effort is required to read the user
information of the browsing computer? Is it possible? I am using IIS 5.0 and
IE 5.5+.
Thanks,
Sam Carl