how to call base implementation of method from base

  • Thread starter Thread starter John Rivers
  • Start date Start date
J

John Rivers

is there a way to invoke the (local?) base implementation of a virtual
method from the same class?

class A {
protected virtual void Blah() {
throw new Exception("never hits here");
}
public void Fud() {
this.Blah(); // hmmm invokes most derived // same as Blah();
}
}

class B : A {
protected override void Blah() {
// stuff
Fud();
// more stuff
}
}
 
is there a way to invoke the (local?) base implementation of a virtual
method from the same class?
Click to expand...

No. You have to provide alternate access to the base method if you really
need to call it. More than likely, though, this is a flag that you need to
re-think your design.
 
No. You have to provide alternate access to the base method if you really
need to call it. More than likely, though, this is a flag that you need to
re-think your design.
Click to expand...

It is easy enough to move behaviour into a non-virtual method
it just seemed strange to have a syntax that didn't behave as it read

Blah() is no different to this.Blah()
but in derived class this.Blah() and base.Blah() are very different
 
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