Extract text from a string

[Guest]

I have the following cells

A1 = Joe Bloggs[20%]
A2 = Fred Astair[5%]

I would like to pull the percentage out of the name into another cell. At
the moment I have

MID(A1,SEARCH("[",A1)+1,3)

However this won't work for a percentage under 10, like 5%.
Also, there are occasions when there is no percentage in brackets, just the
person's name - is there a way of allowing for this without using an extra IF
statement?

Thanks,

Ellebelle

 

[Guest]

Ellebelle

Well I couldn't manage it without IF statements, will this do?

=IF(LEN(MID(A1,SEARCH("[",A1)+1,3))=1,"",IF(RIGHT(MID(A1,SEARCH("[",A1)+1,3),1)="]",MID(A1,SEARCH("[",A1)+1,2),MID(A1,SEARCH("[",A1)+1,3)))

Mike

 

[Haldun Alay]

Hi,

Try following formula...

=IF(ISERROR(SEARCH("[",A1)),"",SUBSTITUTE(SUBSTITUTE(MID(A1,SEARCH("[",A1),(LEN(A1)-SEARCH("[",A1))+1),"[",""),"]",""))

 

[Roger Govier]

Hi Ellebelle

Try
=SUBSTITUTE(MID(A1,SEARCH("[",A1)+1,3),"]","")

 

[RagDyeR]

You can use TTC (Text To Columns), Delimited,
With the left square bracket as the delimiter.

After the primary separation, use Edit & Replace to eliminate the right
square bracket.

This gives you actual data, with *no* ensuing formulas to deal with.
--

HTH,

RD
=====================================================
Please keep all correspondence within the Group, so all may benefit!
=====================================================

I have the following cells

A1 = Joe Bloggs[20%]
A2 = Fred Astair[5%]

I would like to pull the percentage out of the name into another cell. At
the moment I have

MID(A1,SEARCH("[",A1)+1,3)

However this won't work for a percentage under 10, like 5%.
Also, there are occasions when there is no percentage in brackets, just the
person's name - is there a way of allowing for this without using an extra
IF
statement?

Thanks,

Ellebelle