J
jrpisci
Can someone explain to me what this code is doing? I have worked with
arrays in C++ but not VB. I don't know the VB code meanings.... A line
by line woud be very helpful.....
thanks
Dim BrassTag1 As String
Dim BrassTag2 As String
Dim LoadData1 As String
Dim LoadData2 As String
Dim LoadData3 As String
Dim LoadData4 As String
Dim loadnum() As String
Dim m_stLoadNumber As String
m_stLoadNumber = "BT540861_20060428043148"
'take the BT off the loadnumber
loadnum = Split(m_stLoadNumber, "BT")
'break up loadnumber into brasstag and load date
loadnum = Split(loadnum(1), "_")
'break the brasstag into 2 parts
BrassTag1 = Left(Format(loadnum(0), "000000"), 3)
BrassTag2 = Right(loadnum(0), 3)
'break up the load date into 4 parts
LoadData1 = Left(loadnum(1), 4)
LoadData2 = Mid(loadnum(1), 5, 4)
LoadData3 = Mid(loadnum(1), 9, 4)
LoadData4 = Right(loadnum(1), 2)
arrays in C++ but not VB. I don't know the VB code meanings.... A line
by line woud be very helpful.....
thanks
Dim BrassTag1 As String
Dim BrassTag2 As String
Dim LoadData1 As String
Dim LoadData2 As String
Dim LoadData3 As String
Dim LoadData4 As String
Dim loadnum() As String
Dim m_stLoadNumber As String
m_stLoadNumber = "BT540861_20060428043148"
'take the BT off the loadnumber
loadnum = Split(m_stLoadNumber, "BT")
'break up loadnumber into brasstag and load date
loadnum = Split(loadnum(1), "_")
'break the brasstag into 2 parts
BrassTag1 = Left(Format(loadnum(0), "000000"), 3)
BrassTag2 = Right(loadnum(0), 3)
'break up the load date into 4 parts
LoadData1 = Left(loadnum(1), 4)
LoadData2 = Mid(loadnum(1), 5, 4)
LoadData3 = Mid(loadnum(1), 9, 4)
LoadData4 = Right(loadnum(1), 2)