Declaring an array within a structure

  • Thread starter Thread starter Guest
  • Start date Start date
G

Guest

Hi All,

I need to declare an array in a structure. The following gives an error at
private char[] chararr = new char[5];
------------------------------------------------------
struct SimpleStruct
{
private int xval;
private char[] chararr = new char[5];

public SimpleStruct(int intval, char[] chararrval)
{
xval = intval;
for(int i = 0; i < 5; i++)
{
charr = chararrval;
}
}
}

Could anybody please post the correct declaration?

Thanks,
kd.
 
You have to declare that property inside the constructor. Make it like so:

struct SimpleStruct
{
private int xval;
private char[] chararr;

public SimpleStruct(int intval, char[] chararrval)
{
chararr = new char[5];
xval = intval;

for(int i = 0; i < 5; i++)
{
charr = chararrval;
}
}
}
 
And on second examination, it looks like you're trying to do this...

struct SimpleStruct
{
private int charsLength;
private char[] chars;

public SimpleStruct(char[] input)
{
charsLength = input.Length;
chars = new char[charsLength];
Array.Copy( input, chars, charsLength );
}
}
 
Nick Baldwin said:
And on second examination, it looks like you're trying to do this...

struct SimpleStruct
{
private int charsLength;
private char[] chars;

public SimpleStruct(char[] input)
{
charsLength = input.Length;
chars = new char[charsLength];
Array.Copy( input, chars, charsLength );
}
}
Click to expand...

Alternatively:

chars = (char[]) input.Clone();
 
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