Creating a new Field from and existing field

  • Thread starter Thread starter LOgle via AccessMonster.com
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LOgle via AccessMonster.com

Can I create a new field in my table from a Date field that holds example
BegWkExp: 06/16/97 and then the other field has Yrs Exp: 9 I know I can use
this formula to calculate it in a form
=DateDiff("yyyy", [begwkexp], Date) but I am not sure how to just make it a
new field in the table. Can I do this??

Thanks!

--
Thank You!

LOgle

Message posted via AccessMonster.com
 
If you are using Access (a relational database), you don't need to store a
calculated field in your table. Not only would that create synchronization
issues you'd have to deal with, it takes up room you don't need to.

Instead, create a query that calculates the "Years of Experience" from the
existing date/time field.

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Regards

Jeff Boyce
Microsoft Office/Access MVP
Microsoft IT Academy Program Mentor
 
Can I create a new field in my table from a Date field that holds example
BegWkExp: 06/16/97 and then the other field has Yrs Exp: 9 I know I can use
this formula to calculate it in a form
=DateDiff("yyyy", [begwkexp], Date) but I am not sure how to just make it a
new field in the table. Can I do this??

Storing derived data such as this in your table accomplishes
three things: it wastes disk space; it wastes time (almost
any calculation will be MUCH faster than a disk fetch); and
most importantly, it risks data corruption. If one of the
underlying fields is subsequently edited, you will have data
in your table WHICH IS WRONG, and no automatic way to detect
that fact.

Just redo the calculation whenever you need it, either as a
calculated field in a Query or just as you're now doing it -
in the control source of a Form or a Report textbox.


John W. Vinson[MVP]
 
I put it on a form. Thanks!

John said:
Can I create a new field in my table from a Date field that holds example
BegWkExp: 06/16/97 and then the other field has Yrs Exp: 9 I know I can use
this formula to calculate it in a form
=DateDiff("yyyy", [begwkexp], Date) but I am not sure how to just make it a
new field in the table. Can I do this??

Storing derived data such as this in your table accomplishes
three things: it wastes disk space; it wastes time (almost
any calculation will be MUCH faster than a disk fetch); and
most importantly, it risks data corruption. If one of the
underlying fields is subsequently edited, you will have data
in your table WHICH IS WRONG, and no automatic way to detect
that fact.

Just redo the calculation whenever you need it, either as a
calculated field in a Query or just as you're now doing it -
in the control source of a Form or a Report textbox.

John W. Vinson[MVP]

--
Thank You!

LOgle

Message posted via AccessMonster.com
 
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