Calculate Duration.

  • Thread starter Thread starter Guest
  • Start date Start date
G

Guest

Need Help..

I would like to subtract the end time(hh:mm:ss) from the start
time(hh:mm:ss) to get the duration (HH:MM:SS) of how long a job took to
process.

Thanks.
 
Need Help..

I would like to subtract the end time(hh:mm:ss) from the start
time(hh:mm:ss) to get the duration (HH:MM:SS) of how long a job took to
process.

Thanks.

Wouldn't you rather do it the other way round?

Start in A2
End in B2
Format of A2 and B2 to 13:30:55
Duration in C2: =B2-A2
Set format of C2 to [h]:mm:ss
 
Hi Art

Sub test()
Dim t As Date, tt As Date
t = Now
'Your code
tt = Now
MsgBox Format((tt - t), "hh:mm:ss")
End Sub
--


XL2003
Regards

William
(e-mail address removed)
 
Dodo & William

I have encountered this error. Could you tell me what I'm missing.

c3 = 22:47:00
c2 = 00:01:00

answer: ##############

I only get the above answer when using the midnight time.
 
Did you use:
=c2-c3

If you did, then when excel sees negative times (or dates), it shows them as
####'s.

You can avoid this by using the 1904 base date system.

Tools|Options|calculation tab is where you'd toggle this.

But if you have any dates in that workbook, they'll change by 4 years and one
day.

If c2 is the following day, you could do this:

=c2-c3+if(c2<c3,24,0)
or shorter
=c2-c3+(c2<c3)

A more robust way would be to enter both the date and time in each cell.
 
Thanks Dave that did it..

Dave Peterson said:
Did you use:
=c2-c3

If you did, then when excel sees negative times (or dates), it shows them as
####'s.

You can avoid this by using the 1904 base date system.

Tools|Options|calculation tab is where you'd toggle this.

But if you have any dates in that workbook, they'll change by 4 years and one
day.

If c2 is the following day, you could do this:

=c2-c3+if(c2<c3,24,0)
or shorter
=c2-c3+(c2<c3)

A more robust way would be to enter both the date and time in each cell.
 

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