average in formula?

[fivermsg]

how would i get the total of this equation
(((E5*1.05)/(E4*1.05))+((E6*0.89)/(E4*0.89))+((E7/E4)/(E4*60))) to
average?? meaning adding each inner equation and dividing by 3 won't
work cause sometimes these inner equations will =0 ... I want the
average of the inner equations omitting any zero values

 

[Bob Phillips]

=AVERAGE((E5*1.05)/(E4*1.05),(E6*0.89)/(E4*0.89),(E7/E4)/(E4*60))

--

HTH

Bob Phillips

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[fivermsg]

so what you are saying is that if one of those inner formulas =0 then it
would omit that one and just average the other two?

 

[Bob Phillips]

Revise that

=SUM((E5*1.05)/(E4*1.05)+(E6*0.89)/(E4*0.89)+(E7/E4)/(E4*60))/COUNT(E5:E7)

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

=AVERAGE((E5*1.05)/(E4*1.05),(E6*0.89)/(E4*0.89),(E7/E4)/(E4*60))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

message news:[email protected]...

 

[Guest]

=(((E5*1.05)/(E4*1.05))+((E6*0.89)/(E4*0.89))+((E7/E4)/(E4*60)))/COUNTIF(E5:E7,">0")

OR

=SUM((E5*1.05)/(E4*1.05)+(E6*0.89)/(E4*0.89)+(E7/E4)/(E4*60))/COUNTIF(E5:E7,">0")

 

[David Biddulph]

Revise that

=SUM((E5*1.05)/(E4*1.05)+(E6*0.89)/(E4*0.89)+(E7/E4)/(E4*60))/COUNT(E5:E7)

Presumably you could omit the two occurrences of "*1.05", and similarly of
"*0.89"?

 

[Bob Phillips]

No, that was my mistake, I revised it in a later post.

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

 

[Bob Phillips]

Are you asking that, or just stating it?

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)