Allocating a continuous block of memory for a structure?

[Kourosh]

I have a structure that has a byte array as a field:
struct foo
{
public int A;
public int B;
public byte[] C;
}

I want to create an instance of this structure, such that all fields
A, B, and C are in a continous block of memory. Right now if I assign
C a new byte array, it gets created in a different spot in memory than
fields A and B.
Is there any way i can do this?

 

[Willy Denoyette [MVP]]

I have a structure that has a byte array as a field:
struct foo
{
public int A;
public int B;
public byte[] C;
}

I want to create an instance of this structure, such that all fields
A, B, and C are in a continous block of memory. Right now if I assign
C a new byte array, it gets created in a different spot in memory than
fields A and B.
Is there any way i can do this?

Not sure why you need this for, anyway, the only possible way is to declare
the array of fixed size in an unsafe block.

unsafe struct foo
{
public int A;
public int B;
fixed public byte[128] C; // embedded array of 128 bytes
}

Note both requirement; fixed size and unsafe.

Willy.

 

[Jon Skeet [C# MVP]]

Not sure why you need this for, anyway, the only possible way is to declare
the array of fixed size in an unsafe block.

unsafe struct foo
{
public int A;
public int B;
fixed public byte[128] C; // embedded array of 128 bytes
}

Note both requirement; fixed size and unsafe.

Also note that this is only available as of C# 2.