Image Processing PPC

I have an C# PPC app and am experiencing extream lag time when manipulating
pixel values in an Image object. Is there a way to make the GetPixel /
SetPixel operation faster ?

my image is 144x256 pixel and takes about 3 minutes to simply invert the
colors using the following code:

**********************************************************
if (chkInvert.Checked)
{
Color tmpclr, newClr;
int r, g, b;
Bitmap img2Invert = new Bitmap(pictureBox1.Image);

//loop through the image and invert each pixel
for (int iy = 0; iy < img2Invert.Height; iy++)
for (int ix = 0; ix < img2Invert.Width; ix++)
{
tmpclr = img2Invert.GetPixel(ix, iy);
r = 255 - tmpclr.R;
g = 255 - tmpclr.G;
b = 255 - tmpclr.B;
newClr = Color.FromArgb(r, g, b);
img2Invert.SetPixel(ix, iy, newClr);

}

pictureBox1.Image = img2Invert;
}

************************************************************

Help with this would be much appreciated.

No, there's no way to make Get/SetPixel faster. Please use LockBits and
access bitmap data directly instead (NETCF V2 only).


--
Best regards,

Ilya

This posting is provided "AS IS" with no warranties, and confers no rights.

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"digiwizard" <digiwizard@discussions.microsoft.com> wrote in message
news:028334F0-0D62-4EB1-8FAB-A2208A408387@microsoft.com...
>I have an C# PPC app and am experiencing extream lag time when
>manipulating
> pixel values in an Image object. Is there a way to make the GetPixel /
> SetPixel operation faster ?
>
> my image is 144x256 pixel and takes about 3 minutes to simply invert the
> colors using the following code:
>
> **********************************************************
> if (chkInvert.Checked)
> {
> Color tmpclr, newClr;
> int r, g, b;
> Bitmap img2Invert = new Bitmap(pictureBox1.Image);
>
> //loop through the image and invert each pixel
> for (int iy = 0; iy < img2Invert.Height; iy++)
> for (int ix = 0; ix < img2Invert.Width; ix++)
> {
> tmpclr = img2Invert.GetPixel(ix, iy);
> r = 255 - tmpclr.R;
> g = 255 - tmpclr.G;
> b = 255 - tmpclr.B;
> newClr = Color.FromArgb(r, g, b);
> img2Invert.SetPixel(ix, iy, newClr);
>
> }
>
> pictureBox1.Image = img2Invert;
> }
>
> ************************************************************
>
> Help with this would be much appreciated.
>
>
>
>
>

Thanks! I appriciate the help...^_^

If you could provide an example of LockBits it would be great -- meanwhile
I'll query msdn for it. :]

~Digiwizard~

"Ilya Tumanov [MS]" wrote:

> No, there's no way to make Get/SetPixel faster. Please use LockBits and
> access bitmap data directly instead (NETCF V2 only).
>
>
> --
> Best regards,
>
> Ilya
>
> This posting is provided "AS IS" with no warranties, and confers no rights.
>
> *** Want to find answers instantly? Here's how... ***
>
> 1. Go to
> http://groups-beta.google.com/group...framework?hl=en
> 2. Type your question in the text box near "Search this group" button.
> 3. Hit "Search this group" button.
> 4. Read answer(s).
>
> "digiwizard" <digiwizard@discussions.microsoft.com> wrote in message
> news:028334F0-0D62-4EB1-8FAB-A2208A408387@microsoft.com...
> >I have an C# PPC app and am experiencing extream lag time when
> >manipulating
> > pixel values in an Image object. Is there a way to make the GetPixel /
> > SetPixel operation faster ?
> >
> > my image is 144x256 pixel and takes about 3 minutes to simply invert the
> > colors using the following code:
> >
> > **********************************************************
> > if (chkInvert.Checked)
> > {
> > Color tmpclr, newClr;
> > int r, g, b;
> > Bitmap img2Invert = new Bitmap(pictureBox1.Image);
> >
> > //loop through the image and invert each pixel
> > for (int iy = 0; iy < img2Invert.Height; iy++)
> > for (int ix = 0; ix < img2Invert.Width; ix++)
> > {
> > tmpclr = img2Invert.GetPixel(ix, iy);
> > r = 255 - tmpclr.R;
> > g = 255 - tmpclr.G;
> > b = 255 - tmpclr.B;
> > newClr = Color.FromArgb(r, g, b);
> > img2Invert.SetPixel(ix, iy, newClr);
> >
> > }
> >
> > pictureBox1.Image = img2Invert;
> > }
> >
> > ************************************************************
> >
> > Help with this would be much appreciated.
> >
> >
> >
> >
> >
>
>
>