here is the simplified code: the myCor is set to null when run the program.
but if remove the "ref" from the constructor's parameter, myCor gets a valid
value.

Please help!!! thanks.


Type myType = myAssembly.GetType("MyClass")
Type[] parameters = new Type[1];
parameters[0] = typeof(object);
ConstructorInfo myCor = myType .GetConstructor(parameters);

public class MyClass
{
public MyClass(ref object obj)
{
object o = obj;
}
}

> here is the simplified code: the myCor is set to null when run the
> program. but if remove the "ref" from the constructor's parameter,
> myCor gets a valid value.

This is not a solution right now, but to be honest, I never have
required the ref-keyword in a constructor... I believe there is a better
way to handle this, seems to me as a week design (maybe I am wrong,
because I don't see the whole context).

Markus

(E-Mail Removed)am <(E-Mail Removed)> wrote:
> here is the simplified code: the myCor is set to null when run the program.
> but if remove the "ref" from the constructor's parameter, myCor gets a valid
> value.

As Markus said, it's very rare to need "ref" in a constructor (and I'd
need to see a good example to persuade me that it's a good idea) but
you can make GetConstructor work. Here's a short but complete example:

using System;
using System.Reflection;

public class MyClass
{
public MyClass(ref object obj)
{
Console.WriteLine ("Called");
}
}

class Test
{
static void Main()
{
Type type = typeof(MyClass);
Type[] parameterTypes = new Type[]
{ typeof(object).MakeByRefType() };
ConstructorInfo constructor = type.GetConstructor
(parameterTypes);

object[] args = new object[1];
constructor.Invoke(args);
}
}

--
Jon Skeet - <(E-Mail Removed)>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

> Type[] parameterTypes = new Type[]
> { typeof(object).MakeByRefType() };

Cool - thanks for the solution.

Markus