I am running Office 2000 in WinXP.

I have a need to display several dozen .jpg files, each 10 megs or so in
size in a workbook, with 4 or 5 of them accessable from each worksheet.
Placing each entire picture into the workbook, it becomes unwieldy in size.
I have decided to place buttons on each worsheet with thumbnails of the
picture to be displayed on the button, so that when the button is pressed,
the full size file is displayed.

The following VBA code works:

Dim RetVal
RetVal = Shell("rundll32.exe
C:\WINDOWS\system32\shimgvw.dll,ImageView_Fullscreen
picture_name_and_path.jpg", 1)

This displays the full size picture in Windows picture and fax viewer. It is
a solution I can live with. But what I really want to do is to display the
picture using whatever the default .jpg viewer is for that computer just as
if the picture file was double clicked.

There must be some function such as "show using default pic.jpg"

If this is not clear, I can further explain.

Thanks

You have a few choices.
..FollowHyperlink will open it in IE.
The ShellExecute API will open in the app associated with that file type.

Private Declare Function ShellExecute Lib "shell32.dll" Alias
"ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal
lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String,
ByVal nShowCmd As Long) As Long
Const SW_SHOWNORMAL = 1

Private Sub CommandButton3_Click()
Dim RetVal As Long

Const FileName As String = "C:\Sample.jpg"

ThisWorkbook.FollowHyperlink FileName
'or
RetVal = ShellExecute(Application.hwnd, "open", FileName, vbNullString,
"C:\", SW_SHOWNORMAL)

End Sub

Or you could keep it all inside Excel, by using an Image control (on the WS
or modeless userform) and load the picture into that.
That way it is not saved with the WB.

NickHK

"videor" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> I am running Office 2000 in WinXP.
>
> I have a need to display several dozen .jpg files, each 10 megs or so in
> size in a workbook, with 4 or 5 of them accessable from each worksheet.
> Placing each entire picture into the workbook, it becomes unwieldy in
size.
> I have decided to place buttons on each worsheet with thumbnails of the
> picture to be displayed on the button, so that when the button is pressed,
> the full size file is displayed.
>
> The following VBA code works:
>
> Dim RetVal
> RetVal = Shell("rundll32.exe
> C:\WINDOWS\system32\shimgvw.dll,ImageView_Fullscreen
> picture_name_and_path.jpg", 1)
>
> This displays the full size picture in Windows picture and fax viewer. It
is
> a solution I can live with. But what I really want to do is to display the
> picture using whatever the default .jpg viewer is for that computer just
as
> if the picture file was double clicked.
>
> There must be some function such as "show using default pic.jpg"
>
> If this is not clear, I can further explain.
>
> Thanks
>
>
>
>

Thanks for the additional ideas. I got the IE version to work, and the Image
control. However, I can't get the ShellExecute to work. The statement
"retval=shellexecute(..." crashes with a "object doesn't support this
property or method" message. the entire statement is highlighted.

bern muller


"NickHK" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> You have a few choices.
> .FollowHyperlink will open it in IE.
> The ShellExecute API will open in the app associated with that file type.
>
> Private Declare Function ShellExecute Lib "shell32.dll" Alias
> "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal
> lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As
> String,
> ByVal nShowCmd As Long) As Long
> Const SW_SHOWNORMAL = 1
>
> Private Sub CommandButton3_Click()
> Dim RetVal As Long
>
> Const FileName As String = "C:\Sample.jpg"
>
> ThisWorkbook.FollowHyperlink FileName
> 'or
> RetVal = ShellExecute(Application.hwnd, "open", FileName, vbNullString,
> "C:\", SW_SHOWNORMAL)
>
> End Sub
>
> Or you could keep it all inside Excel, by using an Image control (on the
> WS
> or modeless userform) and load the picture into that.
> That way it is not saved with the WB.
>

This is part of the Windows API. Excel/VBA know nothing about it, so you
have include the declarations that I included, in the top section of the
code module:

Private Declare Function ShellExecute Lib "shell32.dll" Alias
"ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal
lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String,
ByVal nShowCmd As Long) As Long
Const SW_SHOWNORMAL = 1

NickHK


"videor" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> Thanks for the additional ideas. I got the IE version to work, and the
Image
> control. However, I can't get the ShellExecute to work. The statement
> "retval=shellexecute(..." crashes with a "object doesn't support this
> property or method" message. the entire statement is highlighted.
>
> bern muller
>
>
> "NickHK" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
> > You have a few choices.
> > .FollowHyperlink will open it in IE.
> > The ShellExecute API will open in the app associated with that file
type.
> >
> > Private Declare Function ShellExecute Lib "shell32.dll" Alias
> > "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal
> > lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As
> > String,
> > ByVal nShowCmd As Long) As Long
> > Const SW_SHOWNORMAL = 1
> >
> > Private Sub CommandButton3_Click()
> > Dim RetVal As Long
> >
> > Const FileName As String = "C:\Sample.jpg"
> >
> > ThisWorkbook.FollowHyperlink FileName
> > 'or
> > RetVal = ShellExecute(Application.hwnd, "open", FileName, vbNullString,
> > "C:\", SW_SHOWNORMAL)
> >
> > End Sub
> >
> > Or you could keep it all inside Excel, by using an Image control (on the
> > WS
> > or modeless userform) and load the picture into that.
> > That way it is not saved with the WB.
> >
>
>

I had done that. But based on your assurance that was what should be done, I
did a little troubleshooting and found the problem:

The call as you sent it was: (without quotes)

"RetVal = ShellExecute(Application.hwnd, "open", FileName, vbNullString,
"C:\", SW_SHOWNORMAL)"

I changed it to:

"RetVal = ShellExecute(hwnd, "open", FileName, vbNullString,
"C:\", SW_SHOWNORMAL)"

and that seems to work. Any reason not to do it that way?

Thanks for all the help.

bern

"NickHK" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
>
> This is part of the Windows API. Excel/VBA know nothing about it, so you
> have include the declarations that I included, in the top section of the
> code module:
>
> Private Declare Function ShellExecute Lib "shell32.dll" Alias
> "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal
> lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As
> String,
> ByVal nShowCmd As Long) As Long
> Const SW_SHOWNORMAL = 1
>
> NickHK

What is your value of hwnd ?

This should be the Windows handle of the parents window, hence
Application.hwnd.
This only works in Excel 2002 and higher.
In earlier versions, you should use the FindWindow API.

NickHK

"videor" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> I had done that. But based on your assurance that was what should be done,
I
> did a little troubleshooting and found the problem:
>
> The call as you sent it was: (without quotes)
>
> "RetVal = ShellExecute(Application.hwnd, "open", FileName, vbNullString,
> "C:\", SW_SHOWNORMAL)"
>
> I changed it to:
>
> "RetVal = ShellExecute(hwnd, "open", FileName, vbNullString,
> "C:\", SW_SHOWNORMAL)"
>
> and that seems to work. Any reason not to do it that way?
>
> Thanks for all the help.
>
> bern
>
> "NickHK" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
> >
> > This is part of the Windows API. Excel/VBA know nothing about it, so you
> > have include the declarations that I included, in the top section of the
> > code module:
> >
> > Private Declare Function ShellExecute Lib "shell32.dll" Alias
> > "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal
> > lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As
> > String,
> > ByVal nShowCmd As Long) As Long
> > Const SW_SHOWNORMAL = 1
> >
> > NickHK
>
>

I am using Excel 2000. Works well for me, and I am too stingy to upgrade.
:-)

The value of hwnd was null. But it worked anyway. In an effort to do it
right, I implemented the following code:

Declarations:

Public Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA"
(ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String,
ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As
Long) As Long
Const SW_SHOWNORMAL = 1

Public Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal
lpClassName As String, ByVal lpWindowName As String) As Long
*********************************************************
On worksheet:

Private Sub CommandButton1_Click()
Dim RetVal As Long
Dim hwind As Long

hwnd = FindWindow(vbNullString, Application.Caption)

RetVal = ShellExecute(hwnd, "open", ThisWorkbook.Path & "\PICT7550.JPe",
vbNullString, "C:\", SW_SHOWNORMAL)

End Sub

That works and delivers some humungous number for hwind. I imagine the extra
code will make it more machine independent. Interesting that it works even
when hwnd is a null. I tried plugging in several arbitrary numbers and they
all worked. Maybe some other display programs will be more fussy.

Thanks yet again for the help and suggestions.


"NickHK" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> What is your value of hwnd ?
>
> This should be the Windows handle of the parents window, hence
> Application.hwnd.
> This only works in Excel 2002 and higher.
> In earlier versions, you should use the FindWindow API.
>
> NickHK
>

Getting the hwnd will yield a Long value for the main Excel window, XLMAIN.
The hwnd is used if some message box needs to be shown or notification sent
to a window.
If the value is not valid, outcome would be unpredictable.
<guess>
As long as that is not the case, the hwnd is probably ignored.
</guess>

For the sake of an extra declaration and one line of code, it worth doing
correctly.

NickHK

"videor" <(E-Mail Removed)> wrote in message
news:8ZydnTkzq8-(E-Mail Removed)...
> I am using Excel 2000. Works well for me, and I am too stingy to upgrade.
> :-)
>
> The value of hwnd was null. But it worked anyway. In an effort to do it
> right, I implemented the following code:
>
> Declarations:
>
> Public Declare Function ShellExecute Lib "shell32.dll" Alias
"ShellExecuteA"
> (ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String,
> ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd
As
> Long) As Long
> Const SW_SHOWNORMAL = 1
>
> Public Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal
> lpClassName As String, ByVal lpWindowName As String) As Long
> *********************************************************
> On worksheet:
>
> Private Sub CommandButton1_Click()
> Dim RetVal As Long
> Dim hwind As Long
>
> hwnd = FindWindow(vbNullString, Application.Caption)
>
> RetVal = ShellExecute(hwnd, "open", ThisWorkbook.Path & "\PICT7550.JPe",
> vbNullString, "C:\", SW_SHOWNORMAL)
>
> End Sub
>
> That works and delivers some humungous number for hwind. I imagine the
extra
> code will make it more machine independent. Interesting that it works even
> when hwnd is a null. I tried plugging in several arbitrary numbers and
they
> all worked. Maybe some other display programs will be more fussy.
>
> Thanks yet again for the help and suggestions.
>
>
> "NickHK" <(E-Mail Removed)> wrote in message
> news:(E-Mail Removed)...
> > What is your value of hwnd ?
> >
> > This should be the Windows handle of the parents window, hence
> > Application.hwnd.
> > This only works in Excel 2002 and higher.
> > In earlier versions, you should use the FindWindow API.
> >
> > NickHK
> >
>
>

I am using Excel 2000. Works well for me, and I am too stingy to upgrade.
:-)

The value of hwnd was null. But it worked anyway. In an effort to do it
right, I implemented the following code:

Declarations:

Public Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA"
(ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String,
ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As
Long) As Long
Const SW_SHOWNORMAL = 1

Public Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal
lpClassName As String, ByVal lpWindowName As String) As Long
*********************************************************
On worksheet:

Private Sub CommandButton1_Click()
Dim RetVal As Long
Dim hwind As Long

hwnd = FindWindow(vbNullString, Application.Caption)

RetVal = ShellExecute(hwnd, "open", ThisWorkbook.Path & "\PICT7550.JPe",
vbNullString, "C:\", SW_SHOWNORMAL)

End Sub

That works and delivers some humungous number for hwind. I imagine the extra
code will make it more machine independent. Interesting that it works even
when hwnd is a null. I tried plugging in several arbitrary numbers and they
all worked. Maybe some other display programs will be more fussy.

Thanks yet again for the help and suggestions.


"NickHK" <(E-Mail Removed)> wrote in message
news:(E-Mail Removed)...
> What is your value of hwnd ?
>
> This should be the Windows handle of the parents window, hence
> Application.hwnd.
> This only works in Excel 2002 and higher.
> In earlier versions, you should use the FindWindow API.
>
> NickHK